You initialize (__init__) your ZoneType model instead of create()'ing. When
you save an initialized it doesn't get an id magically.
I suggest you to use ZoneType.objects.create() whenever possible. But if you
must init your model first; make sure you get() it again to retrieve its id.
Remember
elated.get_accessor_name())
for child_object in r[1][rd]:
query_set.add(child_object)
Thanks for pointing me in the right direction with the query set. It
still seems like the models could do this for me when it looks up the
values from ForeignKeyField objects. If they d
hello,
it would be easier to help if you provided your modes. are you missing
this:
http://docs.djangoproject.com/en/dev/ref/models/relations/#ref-models-relations
for example:
>>> b = Blog.objects.get(id=1)
>>> e = b.entry_set.create(
... headline='Hello',
... body_text='Hi',
... p
I believe I have done my due diligence, but point me in the right direction if
I am missing something.
I am working on a generic importing engine to import various file formats(csv,
fixed length, etc) into django models based on json formatted file definitions.
It needs to do something like th
You know what I am trying to solve this for about 2 days. Thank you so
much it worked :) All my respects to your brain :)
On 26 Mart, 20:04, Karen Tracey wrote:
> On Fri, Mar 26, 2010 at 8:00 PM, Asim Yuksel wrote:
>
> > I've tried this.
> > The model is
>
> > class Advisors(models.Model):
> >
On Fri, Mar 26, 2010 at 8:00 PM, Asim Yuksel wrote:
> I've tried this.
> The model is
>
> class Advisors(models.Model):
> advisorid = models.IntegerField(primary_key=True,
> db_column='advisorId') # Field name made lowercase.
>maphdid = models.ForeignKey(Tblmaphds, db_column='maPhDId') #
>
I've tried this.
The model is
class Advisors(models.Model):
advisorid = models.IntegerField(primary_key=True,
db_column='advisorId') # Field name made lowercase.
maphdid = models.ForeignKey(Tblmaphds, db_column='maPhDId') #
Field name made lowercase.
rank = models.SmallIntegerField()
On Fri, Mar 26, 2010 at 4:31 PM, Asim Yuksel wrote:
> here is the list display
>
>
> http://picasaweb.google.com/110428031719333287170/BaslKsZAlbum#5453042316004332754
>
> I want that to appear in a list display, because that is what the
> client wants :)
>
> I tried writing unicode method , but i
here is the list display
http://picasaweb.google.com/110428031719333287170/BaslKsZAlbum#5453042316004332754
I want that to appear in a list display, because that is what the
client wants :)
I tried writing unicode method , but it has no effect.I dont know
why.And when I try to use maphdid_id, it
On Mar 26, 4:44 pm, Asim Yuksel wrote:
> Yes foreignkey is an object but there must be a way to display the
> value in a list_display. I am a newbie too. self.maphdid.id doesnt
> work
The underlying id field is called "maphdid_id", so you should be able
to use that. But I have no idea why you'd w
Yes foreignkey is an object but there must be a way to display the
value in a list_display. I am a newbie too. self.maphdid.id doesnt
work
On 26 Mart, 06:05, Thierry Chich wrote:
> Le vendredi 26 mars 2010 04:14:51, Asim Yuksel a écrit :
>
> > I have a question about model.ForeignKey field.Foreig
Le vendredi 26 mars 2010 04:14:51, Asim Yuksel a écrit :
> I have a question about model.ForeignKey field.Foreign key fields are
> shown as object in admin page. How can I show them in other types like
> integer type
> for example I have a Model like this:
>
> class Advisor(models.Model):
>
>
I cant show the foreignkey values in a list_display. I tried
raw_id_fields but didnt work
On 25 Mart, 23:18, Shawn Milochik wrote:
> This should help:
>
> http://docs.djangoproject.com/en/1.1/ref/contrib/admin/#raw-id-fields
>
> Shawn
--
You received this message because you are subscribed to t
This should help:
http://docs.djangoproject.com/en/1.1/ref/contrib/admin/#raw-id-fields
Shawn
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-us...@googlegroups.com.
To unsubscribe from this group, s
I have a question about model.ForeignKey field.Foreign key fields are
shown as object in admin page. How can I show them in other types like
integer type
for example I have a Model like this:
class Advisor(models.Model):
advisorid = models.IntegerField(primary_key=True,
db_column='advisorId')
On 8 déc, 13:26, Michael wrote:
> ^ Thanks for that. Have been scratching my head for a while as .id is
> not a field/property for model.user, according to the doco I am
> reading anyway (http://docs.djangoproject.com/en/dev/topics/auth/
> #topics-auth).
When no primary key is explicitely defi
^ Thanks for that. Have been scratching my head for a while as .id is
not a field/property for model.user, according to the doco I am
reading anyway (http://docs.djangoproject.com/en/dev/topics/auth/
#topics-auth).
I should have just tried .id in the first place : \
... actually you'd think chil
OK, this did lead me to the solution though.
It seems that, for the ForeignKeyField the initial value should be the primary
key of the record and not the object referenced. So changing
>> form = IncidentForm(initial={
>>'reporter': request.user,
to
I want it to be possible to be changed. But I also want the initial selection
to be the current user.
So this isn't really a solution. Thanks anyway.
On Nov 26, 2009, at 10:27 AM, esatterwh...@wi.rr.com wrote:
> in your IncidentForm definition set reporter to a ModelChoiceField
> (User.object
in your IncidentForm definition set reporter to a ModelChoiceField
(User.objects.all(), widget=forms.HiddenInput())
then it should work out ok. I usually hide fk fields to a user if i
want the current request.user object, because I don't want to allow
the possibility for it to be changed.
On Nov
I have a (simplified) model
class Incident(models.Model):
title = models.CharField(max_length=128)
when_reported = models.DateTimeField(auto_now_add=True)
reporter = models.ForeignKey(User)
Where User is from auth. When used with a ModelForm, this creates a popup
button with a list
21 matches
Mail list logo
