Hi,
I understand you want to learn Ajax.. So google is your friend:
http://www.xul.fr/en-xml-ajax.html
2012/2/21 dummyman dummyman
> Which is the best place to start with using django and ajax without using
> jquery ?
>
> I meant calling the view function from javascript without using jquery
>
On 2012-02-21, at 12:00 , dummyman dummyman wrote:
> Which is the best place to start with using django and ajax without using
> jquery ?
>
> I meant calling the view function from javascript without using jquery
> features
The closest XMLHttpRequest tutorial? The Mozilla Developer Network is
usu
Which is the best place to start with using django and ajax without using
jquery ?
I meant calling the view function from javascript without using jquery
features
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You can spawn another process in system, and save identification data
of that process in users's session, and then query django for status
of the process. I guess you can also implement long pooling in django
to query for status of the process. But generally if talking about
long pooling it's worth
You can spawn another process in system, and save identification data
of that process in users's session, and then query django for status
of the process. I guess you can also implement long pooling in django
to query for status of the process. But generally if talking about
long pooling it's worth
Hi!
I have a problem with django and ajax.
I am giving requests from ajax which run a process that takes some
time and has many stages. Is there any way to return the various
stages as responses, so the user does not have to see only the loading
image but can also the current status of the process
Thanks Jorge,
Dajax looks very useful. Ill do it with Json though until Dajax
becomes mainstream. Thanks.
On Jun 2, 10:47 am, Jorge Bastida wrote:
> Hello Marc,
>
> You can render a template into an string.
>
> from django.template.loader import render_to_string
> my_template = render_to_string
Hello Marc,
You can render a template into an string.
from django.template.loader import render_to_string
my_template = render_to_string('template.html',{'some':'data'})
If you want to send the list of objects to the browser you can use
serialization into json:
http://docs.djangoproject.com/en/d
Hey,
I have some ajax running on my pages.
I want to have it pass back some objects. However, I am unsure if I
can pass a list of objects back. So far I have only ever passed back
raw xml or text. Can objects be passed and then iterated via the html
template?
Thanks
--~--~-~--~~
Monica,
I recommend this thread:
http://groups.google.com/group/django-users/browse_thread/thread/a26d805427aa643f/c856de7596c3e249?hl=en#c856de7596c3e249
I think it will solve your problem.
[]s
Diego Ucha
On May 9, 2:52 pm, "Monica Leko" <[EMAIL PROTECTED]> wrote:
> On 5/9/08, Richard Dahl <[E
On 5/9/08, Richard Dahl <[EMAIL PROTECTED]> wrote:
>
> I am not sure what the dom1.toxml() does, are you seeing:
>
>
>
>
>
> left="Necklace"/>
>
Yes, I am seeing this text. Darn. :(
--~--~-~--~~~---~--~~
You received this message because
I am not sure what the dom1.toxml() does, are you seeing:
in firebug, to be sure that it is correctly returning the xml? If so
then the problem is most likely within the javascript and you may have
better luck at the googlemaps api group.
-richard
On 5/9/08, Monica Leko <[E
On 5/9/08, Richard Dahl <[EMAIL PROTECTED]> wrote:
>
> I am not sure what javascript library you are using based on the code
Google maps. GXmlHttp is just like XmlHttpRequest
Now I have this in my view:
return HttpResponse(dom1.toxml(), mimetype="text/xml")
And still my var xmlDoc = request
I am not sure what javascript library you are using based on the code
snippet, but you seem to be looking for a javascript object to be
returned that contains XML. What you are returning is simply the text
'hello world' as a plain vanilla http response. You need to return
the type of object that
Hi
I am trying to use some simple AJAX call, and can't get right result.
I am using this Javascript function:
function filterMarkers(){
var request = GXmlHttp.create();
request.open('GET', '/lbs/' + "?q=placeholder, true);
request.onreadystatechange = function() {
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