Yes, but that’s because all of the arguments are optional. That way you can do:
@login_required
def my_view(request):
…
@login_required(login_url=“/login/“)
def other_view(request):
…
- Peter of the Norse
> On Apr 30, 2018, at 12:24 AM, Mike Dewhirst wrote:
>
>> On 30/04/2018 3:35 PM
Stephen
Not really solved except I gave up on decorating when I finally "got"
it. Thanks again.
1. made two new sub-views for the two scenarios and decorated one of
them with login_required
2. factored out all the commonalities into a new undecorated view with
the same name as used in urls
On 30/04/2018 4:30 PM, Stephen J. Butler wrote:
Yes. I don't see it in the documentation for login_required, but I
believe it's so that you can do something like this in your urls.py:
urlpatterns = [
url(r'^example$', login_required(views.example)),
]
That might be an older way of using th
Yes. I don't see it in the documentation for login_required, but I believe
it's so that you can do something like this in your urls.py:
urlpatterns = [
url(r'^example$', login_required(views.example)),
]
That might be an older way of using the decorator? IDK for sure. But you
can see from the
On 30/04/2018 3:35 PM, Stephen J. Butler wrote:
@login_required doesn't take a test function. You need to use
@user_passes_test directly.
Thank you Stephen.
I thought I'd start another thread to ask about my use case of being
able to require login or not depending on whether the content neede
@login_required doesn't take a test function. You need to use
@user_passes_test directly.
On Mon, Apr 30, 2018 at 12:26 AM, Mike Dewhirst
wrote:
> I'm pretty sure this is a not-understanding-python problem rather than a
> Django problem but here goes ...
>
> In a (FBV) view I'm trying to pass a
I'm pretty sure this is a not-understanding-python
problem rather than a Django problem but here goes ...
In a (FBV) view I'm trying to pass a function in to the
login_required decorator. My function is called 'is_login_needed'
and I want the login_required
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