Thanks.
On Fri, Apr 19, 2013 at 4:41 AM, Paul Walsh wrote:
> These are the changes you'll have to make to django-registration, if you
> are using AUTH_USER_MODEL in django 1.5 and inheriting from AbstractUser:
>
>
> https://bitbucket.org/prjts/django-registration/commits/ba31fc3053bfca7eb7a19d9
These are the changes you'll have to make to django-registration, if you
are using AUTH_USER_MODEL in django 1.5 and inheriting from AbstractUser:
https://bitbucket.org/prjts/django-registration/commits/ba31fc3053bfca7eb7a19d912882e50e295adc55
On Friday, 19 April 2013 11:52:55 UTC+3, Paul Wals
James Bennet says above that it is compatible, but the latest
django-registration code is not compatible with custom user models.
RegistrationProfile, for example, still refers directly to User, whereas
the new custom user implementation in Django 1.5 require this to be changed
in order to work
That's good to know. How stable is it?
-scott
Via mobile phone
On Apr 17, 2013, at 3:52 AM, James Bennett wrote:
Current hg tip is actually 1.5-compatible, in the sense that if you want to
use your own User model, you just subclass the provided stuff and plug in
your model, either importing di
Current hg tip is actually 1.5-compatible, in the sense that if you want to
use your own User model, you just subclass the provided stuff and plug in
your model, either importing directly or using the helper function in
Django 1.5.
django-registration does not do this itself because
1. Using Djan
Thanks Scott; that turned out to be the issue. I found those references and
updated them and all is well.
On Apr 16, 2013, at 7:05 PM, Scott Anderson wrote:
> Django registration is not compatible with custom user models in Django 1.5,
> as it directly references django.contrib.auth.models.Use
Django registration is not compatible with custom user models in Django
1.5, as it directly references django.contrib.auth.models.User in several
places.
If you want to maintain your own copy you can swap those refs for those of
your own User model.
-scott
Via mobile phone
On Apr 16, 2013, at 9
On Sunday, April 14, 2013 9:49:32 PM UTC-4, Lee Hinde wrote:
>
> I'm trying to do a 'simple' registration with just a user email and
> password required to create an account. I'm using django-registration with
> django 1.5.1 and have created a custom model and the custom model manager.
>
> I
I'm trying to do a 'simple' registration with just a user email and
password required to create an account. I'm using django-registration with
django 1.5.1 and have created a custom model and the custom model manager.
I can hit all the registration forms just fine and have copied the example
from
request.user.is_anonymous() and django.contrib.auth.logout()
respectively.
On Feb 24, 2:36 pm, CrabbyPete wrote:
> I have code that allows an anonymous user to look at some elses page,
> but I want to limit what they can do so I have the following code
>
> def show(request):
> u = request.
On Feb 24, 2:36 pm, CrabbyPete wrote:
> I have code that allows an anonymous user to look at some elses page,
> but I want to limit what they can do so I have the following code
>
> def show(request):
> u = request.GET['friend']
> user = User.objects.get(pk=u)
> visit = user.is_auth
I have code that allows an anonymous user to look at some elses page,
but I want to limit what they can do so I have the following code
def show(request):
u = request.GET['friend']
user = User.objects.get(pk=u)
visit = user.is_authenticated()
visit should be false, but it keeps com
Whoops. I figured it out. Even though the user is None, it is failing the
form.is_valid() check and so skipping the if statements. So I just need to
include an else clause for the form.is_valid() check to catch the blank
password situation.
Here's hoping this helps someone else.
On Wed, Feb 17, 2
I am using a basic authentication/login scheme in Django 1.1.1 and
Python 2.5.3. It behaves correctly if I login correctly, or if I use
use a correct username but wrong password. It also works for an
unknown username AND any password. However, if I type in a username
that is not in the database wit
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