So i need to set USE_ETAGS=True in settings.py
And then
return response.status_code=204
Hmm..i'll try it tomorrow at work.
On Mar 12, 6:27 pm, "Horst Gutmann" <[EMAIL PROTECTED]> wrote:
> 2007/3/12, shevken <[EMAIL PROTECTED]>:
>
>
>
> > A
Anyway to return response code 204 from a view?
So that the request page do not get refreshed.
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On Mar 12, 12:39 pm, "shevken" <[EMAIL PROTECTED]> wrote:
> Hi Guys,
>
> I do not want a certain view to refresh my html page.
>
> so I got this method,
>
> def silent_update():
># Do secret s
Hi Guys,
I do not want a certain view to refresh my html page.
so I got this method,
def silent_update():
# Do secret stuff
return HttpResponseNotModified()
---
But i got this error:
Traceback (most recent call last):
File "C:\Python24\
class Message(models.Model):
description = models.CharField(maxlength=200)
author = models.ForeignKey(User)
temp = models.CharField(maxlength=100)
When i syncdb, i do not want the column temp to be created. Is there
any arguments i can pass to enable this?
Eg.
temp = models.CharFie
Hi All,
Is there a way to change the default path of the image to use
backslash (/../) instead of the forward slash?
I declared the following in my model
img = models.ImageUpload(upload_to='upload/img/')
but in the database the column's value is saved as upload\img
\django.jpg
When i display
Hey guys,
How do you de-serialize the object back at the ajax response.
class Cart(models.Model):
...
def get_total_quantity():
return quantity;
self.response = self.xmlhttp.responseText;
// parse the response into a JSON object
var json_data = self.response.parseJSON();
alert(jso
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