On Wednesday 02 January 2008 06:15 pm, Alex Koshelev wrote:
> The second variant with GET query is the best. One resouce has one
> uri but with query you specify it's display properties.
I agree, and have modified my dev site to match that, using Ned
Batchelder's tip of meta tags to solve the ro
I really like Django's policy of readable URLs and one authoritative
page. My question is how do I do printable versions of those nice
and authoritative urls?
Say I have this:
http://www.site.com/articles/slug
I can think of two general ways:
http://www.site.com/print_articles/slug
http://www
From the docs, there are two html tag-related filters: striptags and
removetags. The former removes all tags and the latter a list of
banned tags. Is there a similar tag but that has an *allowed* list
of tags? E.g., could allows and and only those?
Thanks,
Mordy
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On Monday 14 May 2007 10:54 am, Mordy Ovits wrote:
> I think it would make more sense to use random.shuffle()
And (after checking the python docs because I still think in Python
1.5.2), random.sample() makes even more sense.
Mordy
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On Friday 11 May 2007 07:03 pm, Benjamin Slavin wrote:
> I've just uploaded a template filter called "several_random" to the
> django snippets site.
> http://www.djangosnippets.org/snippets/230/
The way you're picking indices is inefficient:
while len(picked_indices) < arg:
candidate = random
On Friday 11 May 2007 06:18 pm, orestis wrote:
> Put in a simple, hard coded python list and use random on this ?
Straight-up random will create dupes.
My current thinking is to have python code creeate a list of 3 from 7
sidebar features and in the template have INCLUDEDs surrounded by
IFs.
I have a sidebar in my page design. I have 7 or so features that can
go in a sidebar (links, quote of the day, infostat, on this day in
history, etc.). I have models for each of those features.
I can easily use django to have the template fill those out for every
page, but what I want is to
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