; using Python ?
>
> Etienne
>
> Le 2017-12-10 à 09:30, Marc R a écrit :
>
> I have this in my model:
>
> class Media:
> js = (
>* '/static/plugins/codemirror/lib/codemirror.js',*
> '/static/plugins/codemirror/mode/html
I have this in my model:
class Media:
js = (
* '/static/plugins/codemirror/lib/codemirror.js',*
'/static/plugins/codemirror/mode/htmlmixed/htmlmixed.js',
'/static/plugins/codemirror/addon/fold/foldcode.js',
'/static/plugins/codemirror/addon/fo
Sorry, didn't read to the bottom of your post :)
Why would there be a better way than overriding the default template? that
is the most efficient way and the power of frameworks.
On Saturday, May 25, 2013 11:53:00 AM UTC-4, Branko Majic wrote:
>
> Hello all,
>
> I've posted a similar question
override the template and change it accordingly (you can grab djangos as a
starting point). Google for django admin template override.
On Saturday, May 25, 2013 11:53:00 AM UTC-4, Branko Majic wrote:
>
> Hello all,
>
> I've posted a similar question a couple of months ago, but received no
> a
What are you trying to accomplish?
I believe the doc's talk about this some; but in short, you can only check
the pk if its a new object; otherwise the pk would be set (if you retrieved
the object from the database, or saved before).
I would assume (as i've not run into the issue yet) that on
I'm trying to insert breaks when a row value in a specific column of data
changes; however, it is triggering on the very first call to "ifchanged".
For example:
{% for row in report %}
{% ifchanged row.column2 %} {% endifchanged %}
...print other data...
{% endfor %}
The very first line is a
Anyone? I would really like to know who I can modify the query as its being
built so that for a specific field I can set the "field" to
AES_DECRTYP(fieldname,key) on a select and AES_ENCRYPT(fieldname,key) on
insert/update
On Sunday, 28 April 2013 20:21:48 UTC-4, Marc R wrote:
&g
I have a model where I have used AES_ENCRYPT(value, key) to save data in a
MySQL database. It is set as a varbinary field.
So the issue is; when trying to edit the model in Django, it does not
render a widget for the field.
I've tried the aesfield from github but that does some funky thing wit
did you use Bookmark.objetcs.all().select_related() ?
As this will create a join query... at least for your model you show in the
message I have found that for very complex joins, you need to use raw
query and not a Model.
On Thursday, April 25, 2013 10:44:28 AM UTC-4, Matthieu Bouron wrote
ndrew Boltachev wrote:
>
> Hi. May be you need
>
> active = models.BooleanField(choices=((True,'yes'),(False,'no')))
>
> ?
>
> - With regards, Andrei
>
>
> 2013/4/27 Marc R >
>
>> I've setup a boolean field and get it to display co
I've setup a boolean field and get it to display correctly using this in my
model:
active = models.BooleanField(choices=((1,'yes'),(0,'no')))
However, when I edit a record in the Django Admin, the select field always
shows "yes" regardless of the database value.
Saving "yes" or "no" stores the
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