Re: Immediately Need Help

e, lazy="dynamic")) space_commercial_products=db.relationship("SpaceCommercialProduct", backref=db.backref( "spaces", uselist=True, lazy="dynamic")) space_document=db.relationship("SpaceDocument", backref=db.backref( "spaces

Re: Immediately Need Help

nko hinglish kaisa samjhenga? 😂 >>> >>> Teko field pe unique constraint lagana padenga >>> >>> Teko no wapas 1 se start karneke liye query maarana padenga >>> >>> last_no = Model.objects.filter(categorycode="blah", >>> citycode=

Re: Immediately Need Help

st_no = Model.objects.filter(categorycode="blah", >> citycode="blah-blah").count() >> >> unique_code ="LM" + categorycode >> + citycode + str(last_no + 1) >> >> >> Aisa code likkha toh result milenga 😋 >> >> >>

Re: Immediately Need Help

t; Teko no wapas 1 se start karneke liye query maarana padenga > > last_no = Model.objects.filter(categorycode="blah", > citycode="blah-blah").count() > > unique_code ="LM" + categorycode > + citycode + str(last_no + 1) > > > Aisa code likkha t

Immediately Need Help

I have to create a unique code for each space saved in dbAb db me save krne k lie, wo multiple part me save ho rha hai, multiple models bhi hai uske.1st model se mujhe space category ka name uthana hai 2nd se city code Category alag alg ho skti hai To code genrate hoga LM-categorycode-citycode-0

Project setup

someone reply soon. -- Regards, Kritika Paul rkritikapau...@gmail.com +91-7905147674 -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-user