I have to override the default display of a foreignkey field in a form
and instead display it as a CharField. Currently it displays the
selection's ID but I need to display the label instead
To be clear, the select option would be the default display for the
ForeignKey. At the moment after I've
Thanks again.
On Nov 25, 4:00 pm, Javier Guerra wrote:
> On Wed, Nov 25, 2009 at 10:42 AM, Jamie Pittock
> wrote:
> > Rolando, thanks. Both your and Javier's solutions work. Do they both
> > do the same think in different ways? Is one way better than the other
>
Rolando, thanks. Both your and Javier's solutions work. Do they both
do the same think in different ways? Is one way better than the other
in any way?
On Nov 25, 3:40 pm, Jamie Pittock wrote:
> Well that was ridiculously easy! Thanks very much for responding
> Javier.
>
> O
Well that was ridiculously easy! Thanks very much for responding
Javier.
On Nov 25, 3:25 pm, Javier Guerra wrote:
> On Wed, Nov 25, 2009 at 9:43 AM, Jamie Pittock
> wrote:
> > This is working as expected. However, the view is checking that the
> > project_slug is found,
I have two models, Project and Task. They are related via a foreign
key in the task model.
The view that displays a task is below...
def task_detail(request, project_slug, task_id):
project = get_object_or_404(Project, slug=project_slug)
return object_detail(
Please excuse the subject if it makes no sense.
Simplified, I have two models Pub and Town. Pub has a ForeignKey
field called 'town'. I'm using the generic object_list view to
display all pubs in a particular town (based on a town slug in the
url). Something like this...
def pubs_by_town(requ
Thanks George.
On May 7, 9:32 pm, George Song wrote:
> On 5/7/2009 1:01 PM, Jamie Pittock wrote:
>
> > Basically, am I doing things right, and if so which is the best
> > solution from the above?
>
> Yup, you are doing things correctly as far as I can tell.
>
> A
Hi all -
As the subject suggests, I've wrapped the generic view
date_based.object_detail in another view, and while my solution seem
to be working, as I'm still new to Django, I'd like to check I'm doing
things right with the experts (you!).
I'm creating a blog that has multiple authors. The ur
Malcolm, thanks very much for this. I don't have time to properly
look at this until Monday but I wanted to at least acknowledge before
then my appreciation of your replies. I'll no doubt be back with
either more thanks or more questions.
On Mar 21, 4:55 am, Malcolm Tredinnick
wrote:
> On Sat
Hi all,
I have two models, Provider and Record. Record has the foreign key
provider_id. In my template I'm displaying how many records a
provider has by using object.record__set.count. If Record had a
status field, how would I display how many records with a particular
status a provider had?
Thanks again. I'm still new to all this.
On Mar 7, 9:37 pm, Daniel Roseman
wrote:
> On Mar 7, 8:21 pm, Jamie Pittock wrote:
>
> > Thanks Daniel. Yeah it's just a way of getting the county so I'll try
> > your second option. Could you possibly point me to the
Thanks Daniel. Yeah it's just a way of getting the county so I'll try
your second option. Could you possibly point me to the docs that
explain the double underscore?
On Mar 7, 7:39 pm, Daniel Roseman
wrote:
> On Mar 7, 5:42 pm, Jamie Pittock wrote:
>
>
>
>
>
>
Sorry, the correct url would be domain.com/country/county/
On Mar 7, 5:42 pm, Jamie Pittock wrote:
> Hi,
>
> I have an app with countries and counties. The simplified model is:
>
> class Country(models.Model):
> name = models.CharField(max_length=50)
> sl
Hi,
I have an app with countries and counties. The simplified model is:
class Country(models.Model):
name = models.CharField(max_length=50)
slug = models.SlugField()
def __unicode__(self):
return self.name
class County(models.Model):
name = mode
ful with the specifics, but I do remember
> reading a lot of complaints on this issue so... be careful!
>
> Eric
>
> On Jun 23, 2008, at 10:10 PM, Jamie Pittock wrote:
>
>
>
> > Thank you Gordon (and Joshua) that's really useful.
>
> > I think I'll
Thank you Gordon (and Joshua) that's really useful.
I think I'll use the site-packages folder then. After doing what you
said I've noticed I seem to have multiple installs of Python on my
machine (OSX).
/usr/lib/python2.5/
/Library/Python/2.5/
/opt/local/lib/python2.5/
/Library/Frameworks/Pytho
Hi all - this may well be a very basic question but I'm gonna ask it
anyway as, everyone needs to learn, and I can't find the answer
anywhere else. It's probably more related to Python than Django
but...
If you're installing additional Python libraries such as Imaging or
Markdown, where are they
Hi,
I'm wanting to create a "tumblelog" of sorts made up of content from
several different models within my site and I'm looking for
suggestions on the best way of accomplishing it. The two ideas I have
so far are:
1. Combine the results from different queries into one (as already
discussed her
Hi all,
I'm trying to figure out whether I can use Django's built in auth
system for my needs. I need to limit access to certain areas
depending on whether the user is member of particular groups. Not
groups as in whether they area admins, moderators etc, but more in a
social network type sense
9, 2:20 am, "Russell Keith-Magee" <[EMAIL PROTECTED]>
wrote:
> On 6/28/07, Jamie Pittock <[EMAIL PROTECTED]> wrote:
>
>
>
> > I don't want to code myself into a corner, so when I start looking at
> > features such as allowing users to search all ven
I'm still new to Django so bear with me ;)
I have models for different types of venues (Bars, Clubs, etc).
Because for example, I'd like to use one Rating model across all these
venue Models I'd presumed that I'd need a parent Venue Model, using
some kind of one-to-one relationship (until model i
OK thanks very much for the reply Malcolm.
On Apr 21, 3:47 am, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Fri, 2007-04-20 at 20:00 +0000, Jamie Pittock wrote:
> > Hi all,
>
> > I'm currently planning my first Django application and after a quick
> &
Hi all,
I'm currently planning my first Django application and after a quick
search of groups I need a model structure very similar to that mention
in this thread:
http://groups.google.com/group/django-users/browse_thread/thread/48359c4c0faa797a
Basically I need models for Restaurant, Bar, Hote
That's great. Thanks alot.
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Sorry, I didn't mean add to your browser favourites.
I meant more of a feature built into a website where users can mark an
article/entry as a "favourite" to store or read later. that kind of
thing.
Russell Keith-Magee wrote:
> On 11/10/06, Jamie Pittock <[EMAIL PROTECTED
Morning all,
I'm learning Django and Python as I go. A long shot but does anyone
know of some site code that's been released with some kind of "add to
favorites" feature? I know, it's cheating but I learn much quicker
from examples.
Or alternatively any relevant resources that might help?
Any
I'm refering again to using this code from the cookbook:
http://code.djangoproject.com/wiki/CookBookCategoryDataModelPostMagic
My entry class has an 'assoc_cats' field (assoc_cats =
models.ManyToManyField(Category)).
How can I order the categories to match the __str__ (Home :: Garden)
rather th
Sorry, I missed those last two replies as I was replying myself. I'll
take a look now and check I'm doing things right.
Many thanks.
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To post t
great. I'm sure it's not perfect yet but I ended up with this:
def entries_by_category(request, slug, childslug=None):
if childslug is not None: slug = childslug
category = get_object_or_404(Category, slug=slug)
entry_list_by_category = category.entry_set.order_by('-pub_
Sorry to reply to myself so quickly.
After a bit of refactoring my two views look like this:
def entries_by_category(request, slug):
category = get_object_or_404(Category, slug=slug)
entry_list_by_category = category.entry_set.order_by('-pub_date',
'title')
return render
Hi folks,
I've just started transporting an existing site to Django as a learning
exercise and some quick help would be appreciated.
I'm using some code from the cookbook to allow parent/child categories:
http://code.djangoproject.com/wiki/CookBookCategoryDataModelPostMagic
That's all dandy.
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