Yes I am interested
On Wed, 23 Oct 2024, 6:24 pm Gourav Kumar Dhiman,
wrote:
> Am a Full stack developer .Am interested
>
> https://www.linkedin.com/in/gourav-kumar-dhiman/
>
> On Monday, May 3, 2021 at 10:42:08 AM UTC+5:30 vineet daniel wrote:
>
>> Hi Group,
>>
>> Any one interested in Frontend
hello i am not from the py community so please remove me from this section.
thanks
On Sat, Nov 5, 2022 at 12:06 AM Ammar Mohammed
wrote:
> *Get your Locations object :*
> obj = Locations.objects.get(pk=1)
> *Then get the region:*
>
> obj.region.
Need updates from MERN
On Wed, 9 Feb 2022, 19:21 Dilja E G, wrote:
> How to add django-admin-autocomplete-filter ? in my django filtter?
>
> --
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> To unsubscribe from this group and stop receiving
are',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware']
Hi
I have a form being generated in admin with modelForms. Now what I
want is that whenever there is a foreignkey field, there should be a
add new model field sign next to it, as there is in the form generated
using fieldset in admin.
I was able to get the Date widget, but I am not able to get th
yes thanks mike
mostly i work in linux but i had to see some work on windows and this
problem was little strange. but all well now.
thanks again
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i have found this during working with django on windws.
if i create folder like template, backup (start characters t, b etc)
it wont work because template folder settings in the SETTINGS.py will
be
TEMPLATE_DIRS = (
'c:\myproject\template',
}
it would not work because \t is tab character
the problem seems to be your database installation. you can increase
CharField length by installaing mysql version 5.xx.
also check what database you are using and character set it supports.
On Sep 25, 10:42 am, Sebastian Dahlgren <[EMAIL PROTECTED]>
wrote:
> Hi!
> I have built my site on the Dja
you can try adding
MaxRequestsPerChild 1
to your httpd.conf file and restart apache
then i think you dont' need to restart apache every time.
this is just for testing purpose, for more read documentation on it.
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You received this message beca
can we save django ORM queries in database and execute them later.
suppose i have class
class queries():
qry=models.CharField(maxlength=200)
and i save a query "test.objects.filter(id=5)" in qry
now want to run query stored in qry field
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hi i am having problem with relating objects. i have models as below
class support():
suptype = models.CharField(maxlength=255)
class DispMaster():
dmtype=models.ForeignKey(support)
class DataDispMaster():
ddmmaster=models.ForeignKey(Master)
class Master():
class DataMaster():
d
i think you are using windows.
try adding "MaxRequestsPerChild 1" (without quotes) to
httpd.conf,
you can change this setting later after reading how apache handles
requests. i think that wouldn't be required for you now.
also put your application to the python path (you can try initial
applica
> athttp://82.165.180.35:8088/djproject/
> I can see the first django page. Could not run any application when I
> try to do that by editing urls.py file.
>
> Thanks,
> Swati
>
> On Sep 26, 1:27 pm, Dushyant Sharma <[EMAIL PROTECTED]> wrote:
>
> > i think you have
i think you have not configured httpd.conf and this is why apache can
not identify the request.
read this page
http://www.djangoproject.com/documentation/modpython/
also make entry in httpd.conf
LoadModule python_module /usr/local/apache2/modules/mod_python.so (for
linux)
for windows use your w
> function1(request):
> return function2(request)
no i just want that function2(request) call makes a permanent redirect
(not HttpResponseRedirect, i dont want more burden on urls.py) to
function2 and all the response should be sent from function2 only. it
should never come back to function1
is it possible to return HttpResponse from another function
like i have called a function say furnction1(request) and now is it
possible
function1(request):
#normal statements
#here i call another function
function2(request)
return HttpResponse('bye') #just for exampl
dear Han
you must add path of python.exe, django-admin.py and manage.py to
your system path
you should avoid copying system files here and there as it will cause
problems.
clean approach should be
1. install python (say installed at C:\python25)
2. set path for python.exe
3. install django (wil
is there any performance bottleneck when the size of urls.py goes
large.
if yes how to overcome that.
also if we use same url for a particular group, based on some hidden
action variable in htmls, would it improve performance. like i am
using
if request.method == 'POST':
action =
use RequestContext
http://www.djangoproject.com/documentation/templates_python/#subclassing-context-requestcontext
pass request object to it
c= RequestContext(request, {other objects})
then you can use user.fieldname in your view
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You received
class ThingForm(forms.Form):
name = forms.CharField(max_length=30, required=True, label=_('Name
of the thing'))
photo = forms.Field(widget=forms.FileInput, required=False,
label=_('Photo'), help_text=_('Upload an image (max %s kilobytes)' %
settings.MAX_PHOTO_UPLOAD_SIZE))
def thing_add(
here is model
class Thing(models.Model):
PID=models.ForeignKey(Property)
name = models.CharField(blank=False, null=False, maxlength=30)
photo = models.ImageField(upload_to='images/things/', blank=True,
null=True)
the form
class ThingForm(forms.Form):
name = forms.CharFi
may be you can use ajax for that. i have tried and it works wonders.
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hi it might sound strange but what i am thinking is to use two servers
one for authentication only and one for serving normal content.
authentication server can not come into direct contact with users.
here how it goes.
suppose we have user server USrv and authentication server ASrv.
auth_user ta
i think you should try port 25 at EMAIL_PORT after all you wont loss
anything giving a try
On Jun 14, 6:12 pm, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Thu, 2007-06-14 at 05:35 -0700, Brij wrote:
> > Hi,
>
> > I am using the django.core.mail for sending mail to users in my
> > applicati
at i am trying is creating two projects setup with apache virtual
host. one is interacting with user as we do normally. another is
serving the first project by taking requests and sending response to
the first without letting the user know anything.
On Jun 14, 5:39 pm, Kenneth Gonsalves <[EMAIL PR
has any body used jsonrpc with django if yes kindly help me
here is how to use it but i cant use it with django facing problems
http://json-rpc.org/wiki/python-json-rpc
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how can i use it with HttpResponseRedirect()
like if i wish to use it as return HttpResponseRedirect('/someurl',
RequestContext(request))
is it possible
On Jun 13, 5:42 am, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Tue, 2007-06-12 at 13:27 +, Dushyant Sha
i am building single page for logged in users and anonymous users
where i can use uid for logged in users and show specific things to
them and for this i want to use session variable in template. i am
trying request.session.uid in template where uid is session
variable..
i have set request.sessio
come on somebody pl. reply
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if this is possible or not to apply manipulator on User and on two
models.
i have read previous posts in this regard sugggesting method what i
have used but i am getting errors as above.
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i am trying to add manipulator on default User object. i am getting
name, email and address from the form and trying to fill date_joined
and last_login attributes myself as
user_data['date_joined_date']=datetime.date.today()
user_data['date_joined_time']=(datetime.time()
i can not beleive this i had only to write enctype in capital
ENCTYPE="multipart/form-data"
i am sick
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i am having the same problem i tried adding mysite.pth to site-
packages folder
now i can see the path in python as
/root/workspace/
and
/root/workspace/mysite
settings.py is in mysite directory at /root/workspace also i have
__init_.py there
it show the same error
but if i put the directory my
hi friends
i am trying to upload an image file but i am getting errors.
code is as follows
def thing_add(request):
if request.method == 'POST':
if 'photo' in request.FILES:
# it aint getting here just skip this section
try:
img = Image.open(Stri
hey thanks chrominance for real good helping stuff.
i was not looking at the last line which clearly states that
argument 1 must be string or read-only buffer, not long
your return HttpResponse(str(uu.id))is really helpful
and also thanks for get() and filter(). i'll keep that i
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