entered
but i don't know if you can do this with a model based form or if you
have to manually create it.
On 27 July, 12:35, Daniel Roseman wrote:
> On Jul 27, 12:15 am, AKK wrote:
>
> > Hi, I have a form based on a model which allows users to add comment.
> > A comment is
Is there a way to do this or should i create my own form manually?
Andrew
On Jul 27, 12:15 am, AKK wrote:
> Hi, I have a form based on a model which allows users to add comment.
> A comment is made up of the comment is about, the body, the date and
> time and also who made the comme
Hi, I have a form based on a model which allows users to add comment.
A comment is made up of the comment is about, the body, the date and
time and also who made the comment.
I am mainly interested in the datetime and user fields. What i would
like to know is how i can automatically have these en
Thank you, got it working
On 21 July, 16:55, Daniel Roseman wrote:
> On Jul 21, 4:25 pm, AKK wrote:
>
>
>
> > Thanks, i tried this:
>
> > blog_posts = Post.objects.filter(post_slug=slug)
> > blog_comments = blog_posts.comment_set.all()
>
> >
Thanks, i tried this:
blog_posts = Post.objects.filter(post_slug=slug)
blog_comments = blog_posts.comment_set.all()
but i got this error and i don't know why:
Traceback:
File "C:\ProgLangs\Python25\lib\site-packages\django\core\handlers
\base.py" in get_response
86. response =
Do i need to have a one to many or many to many field for this to
work?
Thanks
Andrew
On 20 July, 22:24, AKK wrote:
> Hello, i currently have two classes in my model:
>
> class Post(models.Model):
> prepopulated_fields = {"post_slug": ("post_title",)}
>
Hello, i currently have two classes in my model:
class Post(models.Model):
prepopulated_fields = {"post_slug": ("post_title",)}
post_title = models.CharField(max_length=750)
post_slug = models.SlugField()
def __unicode__(self):
return self.post_
Thanks, this is what i wanted.
On 20 July, 20:02, Alex Gaynor wrote:
> On Mon, Jul 20, 2009 at 2:00 PM, AKK wrote:
>
> > I kinda know what the problem is here but don't know how to fix it.
>
> > I have this model class Comment(models.Model):
>
> > com
I kinda know what the problem is here but don't know how to fix it.
I have this model class Comment(models.Model):
comment_post = models.ForeignKey('Post')
comment_date = models.DateTimeField('Date comment made')
comment_body = models.TextField()
comment_spam = models.BooleanFiel
Hi, i have a login form using the generic view like so:
(r'^accounts/login/$', 'django.contrib.auth.views.login',
{'template_name': 'blogSite/login.html'}),
but i only want the form to show up if your not logged in, but since
its is a generic view how can i use
if not request.user.is_authentica
hi,
i have a form like this:
User name:
Password:
and the next field is where the user should be redirected assuming
they have the correct details.
When they login i want them to be redirected to myurl.com/blog/ but
what i have above redirects them to myurl
I'm still abit confused.
Does that mean this part in the book is wrong?:
def search(request):
if 'q' in request.GET:
message = 'You searched for: %r' % request.GET['q']
else:
message = 'You submitted an empty form.'
return HttpResponse(message)
I also tried what you
Hi,
I'm working through chapter 7 of the djangobook online. and i've got
the following:
def search(request):
if 'criteria' in request.GET:
message = 'You searched for: %r' % request.GET['criteria']
else:
message = 'You submitted an empty form.'
return HttpResponse(mes
Thanks, thats worked fine. I don't know why my original message has
reproduced itself.
Regards,
Andrew
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Hi,
I've got the django adming setup but if i look at posts for example i
just get a with post object loads of times. How can i it so it
displays the post title?
In my admin.py i have:
admin.site.register(Post)
and the model is:
post_title = models.CharField(max_length=750)
.
post_t
Hi,
I've got the django adming setup but if i look at posts for example i
just get a with post object loads of times. How can i it so it
displays the post title?
In my admin.py i have:
admin.site.register(Post)
and the model is:
post_title = models.CharField(max_length=750)
.
post_t
Hello,
I have a number of views and templates and a list of categories which
i get from my models using:
categories_list = categories.objects.all()
Since i need to display this in multiple (but not all) templates is
there a better way to achieve this than just putting; categories_list
= categor
I added a comma and it worked fine. And i've learned something, i only
thought you needed a comma if there where multiple items.
Many Thanks,
Andrew
On 2 Mar, 00:10, Malcolm Tredinnick wrote:
> On Sun, 2009-03-01 at 14:40 -0800, AKK wrote:
> > Is this
st the code from
> your setting.py file where you specify your processors? Not just the
> strings, but the entire Python structure where you define those.
>
> On Mar 1, 7:51 am, AKK wrote:
>
> > Having looked at the traceback i gather its something to do with the
> > impor
Having looked at the traceback i gather its something to do with the
imports:
Environment:
Request Method: GET
Request URL: http://localhost:8080/
Django Version: 1.0.2 final
Python Version: 2.5.2
Installed Applications:
['django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.se
Thank you. I had forgotten the context instance part but now i've
added that as below:
"render_to_response('blogSite/index.html', locals(),
context_instance=RequestContext(request))"
and i get:
Exception Type: ValueError
Exception Value: Empty module name
but if i take out reque
If you have windows you may want to try this version
http://groups.google.com/group/django-users/msg/5b5f4dee148d0fc3
There wasn't an mysqldb module exe version available for python 2.6
when i looked a few weeks ago.
I installed that and its worked fine.
Andrew
On 28 Feb, 14:23, ches wrote:
>
Actually i thought i have but i haven't, i added:
TEMPLATE_CONTEXT_PROCESSORS = (
"django.core.context_processors.media"
)
to my settings.py (it didn't seem to be in there by default, i don't
know if thats supposed to be the case).
Then when it didn't work i tried creating a simple template
Managed to get it working. Thanks for the help.
Andrew
On 28 Feb, 00:36, Malcolm Tredinnick wrote:
> On Fri, 2009-02-27 at 11:53 -0800, AKK wrote:
> > Sorry I must mean the media url. Are the media_root and the media_url
> > automatically linked?
>
> No. The MEDIA_RO
Sorry I must mean the media url. Are the media_root and the media_url
automatically linked? In my settings.py i have:
C:/Program Files/Apache2.2/myproject/
media/ as the root &
http://localhost:8080/akonline/media/
as the url
and i have an image (imgs/img.jpg) in my C
Hi,
I have a template and I want to get some images out of my media root.
I was wondering is there anyway to automatically return the media root
from settings.py rather than manually specifying it rather each time.
Thanks
Andrew
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You received
Thanks a lot. I guess, I was not reading it well.
On Jul 24, 4:55 pm, "James Bennett" <[EMAIL PROTECTED]> wrote:
> On 7/24/07, akk <[EMAIL PROTECTED]> wrote:
>
> > Traceback (most recent call last):
> > File "", line 1, in
> > File &q
File "", line 1, in
File "/usr/lib/python2.5/site-packages/django/db/models/base.py",
line 40, in __new__
model_module = sys.modules[new_class.__module__]
KeyError: '__console__'
Thanks a lot,
akk
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