You can use sets
On Tue, Jan 25, 2022 at 7:47 AM bnmng wrote:
> Hello,
>
> Is there a built in function that compares two or more lists and returns
> elements common to all?
>
> like this:
>
> def in_both( list_a, list_b ):
> list_c=[]
> for value in list_a:
> if value in list_b:
> list_c.append
Thank you. That set.intersection with list conversion seems like the way
to go. On your second point, well taken. I'll keep that in mind for
future Python questions
On Tuesday, January 25, 2022 at 7:46:58 AM UTC-5 bnmng wrote:
> Hello,
>
> Is there a built in function that compares two or mo
On 25/01/2022 13.46, bnmng wrote:
Hello,
Is there a built in function that compares two or more lists and returns
elements common to all?
The intersect member function almost does that, just combine in with
converting your list to a set:
https://datagy.io/python-intersection-between-list
Hello,
I ran into an intermittent migration issue on Django 4.x and PostgreSQL.
The migrations work fine on Django 3.2.x, but intermittently fail on
Django 4.x with the following exception:
django.db.utils.ProgrammingError: constraint
"polls_questioncontribution_base_question_id_25bfb2a8_fk"
Well, I did it. I frankensteined my way to a working Django 3.0+ and
Channels 3.0 demo project! Here is where I went. I started at:
https://testdriven.io/blog/django-channels/#add-channels. I cannot stress
this enough, I started at the add-channels section! During my time in
following the i
Hello,
Is there a built in function that compares two or more lists and returns
elements common to all?
like this:
def in_both( list_a, list_b ):
list_c=[]
for value in list_a:
if value in list_b:
list_c.append(value)
return list_c
Or this:
def in_all(list_of_lists):
list_a = list_of_lists.po
6 matches
Mail list logo