[image: Screen Shot 2021-07-06 at 9.50.12 AM.png]
Counter works with words also
nice one Simon Charette learned something new :)
On Tue, 6 Jul 2021 at 07:56, DJANGO DEVELOPER
wrote:
> thanks Simon but I am not using postgresql. I am using sqlite3 database.
> so I want a global solution, that wo
thanks Simon but I am not using postgresql. I am using sqlite3 database. so
I want a global solution, that work in all the databases.
On Tue, Jul 6, 2021 at 1:54 AM Simon Charette wrote:
> If you're using a PostgreSQL you might want to look at using a tsvector
> column instead which will ignore
I moved my custom user and userprofile models from my 'common' app into
my 'company' app by way of locking the model tables first (db_table =
"common_user" and so on) and just plain refactoring.
That has all worked sort of as expected in that Company and User models
now appear in the company a
If you're using a PostgreSQL you might want to look at using a tsvector
column instead which will ignore stop words (the, or, of, ...) and map
lexemes to their number of occurrence and position in the lyrics[0].
Assuming you were to index this column you'd be able to efficiently query
it for ex
The error message is very clear send_mass_mail only expect 4 values but
you are passing in more than four.
You should only pass in four values.
datatuple = (
('f_subject', 'f_message','f_email',
['mygm...@gmail.com']),
# second person
('f_subject', 'f_message','f_email',
['sec...@gmail.com'])
)
Thank you Lalit bhai.
it seems to be a solution.
but what if I want to get the result for each single word rather than
single letter?
On Mon, Jul 5, 2021 at 5:43 PM Lalit Suthar
wrote:
> https://www.guru99.com/python-counter-collections-example.html
> Counter can be helpful for this situation
>
BACKENDS.PY
class EmpBackend(ModelBackend):
Emp = get_user_model()
supports_object_permissions = True
supports_anonymous_user = False
supports_inactive_user = False
def authenticate(self, request, email=None, password=None, **kwargs):
if email is None or password is None:
return
try:
username =
This is the message I get when I try to login "Please enter a correct email
and password. Note that both fields may be case-sensitive."
I've changed my code a little in an effort to try to remedy my situation.
I'm really stuck on this. From what I can tell, it's passing the values to
the authen
i am getting this error down when trying to submit my form data to email
{{ ValueError at /contact
too many values to unpack (expected 4)
Request Method: POST
Request URL: http://localhost:8000/contact
Django Version: 3.2.4
Exception Type: ValueError
Exception Value:
too many values to unpack
https://www.guru99.com/python-counter-collections-example.html
Counter can be helpful for this situation
On Mon, 5 Jul 2021 at 17:07, DJANGO DEVELOPER
wrote:
> Hi there.
> I am developing a project based on adding songs to the user's library and
> to the home page.
> other users can also purchas
Hi there.
I am developing a project based on adding songs to the user's library and
to the home page.
other users can also purchase the songs like wise people do shopping on
eCommerce stores.
*Problem:(Question)*
The problem that I want to discuss here is that when a user adds a sing
through dja
Hi and welcome to the django community!
The best way to learn django depends a lot on you skill and experience of
python as well.
If you don't know that much python, I would recommend starting with a good
course or a book about fundamentals in Python. After that I would go to the
following resour
I'm interested
Le dim. 4 juil. 2021 à 9:38 PM, Theresa Taye a
écrit :
> Hello guys,
>
> I need flutter users for a project urgently if you are interested, please
> contact me.
>
> Best regards
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" gro
I have the following two model classes:
```
class Property(models.Model):
"""Represents property class model"""
serial_no =
models.CharField(unique=True,max_length=255,blank=True,null=True)
map_no = models.CharField(max_length=255,blank=True,null=True)
lr_no = models.CharField(ma
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