I don't know what changed but I can't seem to extract valid form data.
(It was working for months previously.)
Below is the function that creates new users when they register.
I store the data in cd. I can print the contents of cd and confirm cd
is a dictionary
but I can't access any values!!!
Fo
I wouldn't think of my models as "glue". I would write down a list of
requirements and call that an app. It obviously won't need to include
Poll and Article because they exist already and can be imported untouched.
Most of the Django books and docs suggest that you segregate
functionality into
oh, I see, but the problem is that I need this scripts to be ran often and
if I make a request to a sandbox, and then this sandbox send other requests
to my server getting and changing data(since some scripts change the data
of my server) this would take too long, and make the server unable to r
> @patch('apps.market.models.House')
Is create house in apps.market.models, or is it somewhere else? If
it's somewhere else, mock it relative to that file eg:
@patch('apps.some_file.House')
> I'm also wondering if it's possible to inspect MockedHouse to see if it has
> for example some tags adde
I would not recommend allowing untrusted users to execute random python on
your server in any way.
The only sandbox ive seen that is well protected is app engine, if you are
hosting your site on app engine, things might be a bit better.
I would recommend sending webhooks or callbacks to users own
Hi Sandro,
Thanks for the link. It looks like you had provided the link to show
additional options in the action drop down on the list page. This is not
what am exactly looking for. I guess my question was not clear. I will try
to explain it in much better way:
1) I have 2 models called Categories
I need to submit two "forms" with "jquery" because i don't want to put two
input buttons in the template.
The problem is that one of them is a model_formset and it needs {{
formset.management_form }}, and i inserted it in the template, but i still
receive the error "ValidationError: ManagementF
Hi All,
Am using flatpage app in my application. I want to send
few additional variables that can be accessible from the flatpage
templates. So how can i accomplish the same?
Thanks and Regards,
Swaroop Shankar V
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I need to submit two forms with jquery and not with two input buttons.
One of them is a model_formset so i have to add {{ form.management_form }},
and i did it, but i still receive the error: "ManagementForm data is
missing or has been tampered with".
How can i resolve it?
Thanks
Max
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Is this what you're talking about?
https://developers.google.com/appengine/docs/python/overview
Still don't understand how this would be used.
Em sábado, 14 de abril de 2012 14h19min01s UTC-3, Andy McKay escreveu:
>
> That's not something I'd ever recommend an untrusted user do. There
> are still
do the filtering part in views.py . templates is meant only for visual
purpose
On Sat, Apr 14, 2012 at 2:21 PM, Nikhil Somaru wrote:
> Greetings,
>
>
> I would like to do something like queryset filtering in a template. Is the
> only solution via a template tag?
>
>
> # models.py
>
> class Stude
Sounds very goofy. django-admin.py just creates files, doesn't open any
editors so there is somthing really fishy going on in your machine...
On Sat, Apr 14, 2012 at 8:27 PM, Brandy wrote:
> What I mean is, I can create 2 or 3 new projects without problems. I play
> with them and create files, e
Hello,
I have quite interesting problem with password protected content in Django.
I can successfully protect my content or URLs in Django by using
"@login_required" decorator.
Example:
**Urls.py**
urlpatterns = patterns('',
url(r'^(?P[a-zA-Z0-9_.-]+)/$', 'example.sort'),
)
**Views.py**
What I mean is, I can create 2 or 3 new projects without problems. I play
with them and create files, etc. Then, for whatever reason, when I run
django-admin.py startproject again, an editor widow opens
(emacs in my case, since that is what I was using), and django doesn't
create any files. Al
That's not something I'd ever recommend an untrusted user do. There
are still many ways that could go wrong. The safest execution
environment I've seen for Python is App Engine, send a callback to
that instead :)
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Hello!
I want to get just the top element of one queryset. SO I have
something as
qs=MyModel.objects.filter(...).order_by(..)
and then use qs[0] and check some value
I wonder now if i did the right thing or it is better to use .extra on
queryset.
Is the queryset object allocated for all objects,
Hi there, I'm doing a system where I want the users to be able to
set/change some scripts that are dynamically run(RPG like scripts).
So a user can change the way the Kill_a_player script is run.
I thought of doing this by using exec, like this:
class Script(models.Model):
> script_py = mod
Hello everyone,
What is your aproach or what app do you use in order to make translations
for django flatpages and project apps models?
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nevermind, I found the answer:
/usr/local/bin/django-admin.py already existed. I removed it and reran a
fresh install.
On Sat, Apr 14, 2012 at 3:50 PM, BuckRogers wrote:
> Hi,
>
> I am attempting to install Django 1.4 on OS X 10.6.8
>
> After running the following command :
> sudo python s
Say that there's an excellent 3rd party app "articles" with a model
Article and another most excellent 3rd party app "polls" with a model
Poll. How do you glue them together?
If an Article may have several Polls and a Poll may be used in several
Articles, you can glue them together with a new mode
Hi,
I am attempting to install Django 1.4 on OS X 10.6.8
After running the following command :
sudo python setup.py install
I get this (see the last line):
...
copying django/views/generic/list_detail.py -> build/lib/django/views/
generic
copying django/views/generic/simple.py -> build/lib/djan
Make sure that you have 'django.middleware.common.CommonMiddleware' in your
list of MIDDLEWARE_CLASSES. Otherwise APPEND_SLASH has no effect.
- Chris
On Sat, Apr 14, 2012 at 04:15, graeme wrote:
> I have the following setup using Django 1.3:
>
> 1) Middleware that changes request.urlconf depend
I am following the Django tutorial (https://docs.djangoproject.com/en/
1.4/intro/tutorial01/#activating-models) and when I got to running
"python manage.py sql polls" it did not print any output. It did not
print any errors, nor the expected SQL statements. I assumed that
because "exact output will
Hello,
I'm trying to test a function that imports and acts upon a django model, named
House.
from apps.market.models import House
def create_house(location, date, price):
house = House(id=None, date, price)
house.save()
# calculate some stuff and further expand the hous
I have added django-breadcrumbs to my app, following the instructions at
https://github.com/chronossc/django-breadcrumbs/.
It works in so far as there is always exactly one breadcrumb displayed on
each page in my app, but never do more accumulate.
I'm about to try storing the list in the session,
I have the following setup using Django 1.3:
1) Middleware that changes request.urlconf depending on the domain
requested
2) APPEND_SLASH = True
3) One URL pattern that does not end in a slash.
A request for a URL that matches the the pattern that does not end in
a slash is redirected. It works w
Greetings,
I would like to do something like queryset filtering in a template. Is the
only solution via a template tag?
# models.py
class StudentProfile(models.Model):
# class defined here
# ...
class Department(models.Model):
# ...
students = models.ManyToManyField('StudentProfile', nu
Actually it can be fixed by removing django.notifications like so:
Edit `settings.py` by commenting out
"notification.context_processors.notification", within
TEMPLATE_CONTEXT_PROCESSORS and "notification", # must be first from
INSTALLED_APPS. Finally edit urls.py by commenting out
url(r"^notices/
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