Hi all,
Reading between lines, I think that what the original poster wants is
just to be able to compute FFTs that overlap by 1/4 of the FFT size.
So, essentially what JM suggests:
fft2=fft(x(P+1:P+Q))
fft3=fft(x(2*P+1:2*P+Q))
fft4=fft(x(3*P+1:3*P+Q))
How to do this in GNU Radio? You can "
Daniel,
Thanks for the explanation of how to implement JM’s solution in GNU Radio. And
thanks to JM for the discussion.
This should get me over my initial stumbling block to get started.
Jim
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