Hi,
How to calculate how much is the ppm from the error value, which is
actually the drift. If suppose my sample rate is 48KHz and the accumulated
error after 1M samples (20.833 sec) is 'n' samples, then ppm = n, Is
that correct calculation ?
On Thu, Oct 27, 2016 at 3:24 AM, Marcus Müller
wr
On Thu, Oct 27, 2016 at 10:35:32PM +, Fons Adriaensen wrote:
> time constant of around 10 / B, i.e. one second. So the relativei
Correction : of around 1 / (10 * B), i.e. one second.
--
FA
A world of exhaustive, reliable metadata would be an utopia.
It's also a pipe-dream, founded on self-
On Wed, Oct 26, 2016 at 11:54:17PM +0200, Marcus Müller wrote:
> > The actual frequency of the clock used to measure time doesn't
> > matter as long as it has reasonable short term stability (and both sides
> > use the same clock of course).
> Exactly; that what was I was worried about. I don't ha
Hi Fons,
On 10/26/2016 10:26 PM, Fons Adriaensen wrote:
> On Wed, Oct 26, 2016 at 01:30:19PM +0200, Marcus Müller wrote:
>
>> Now, these microsecond timestamps
>> will introduce a /third/ clock into our problems. I can see how the
>> control loop converges in case of that clock being both faster t
On Wed, Oct 26, 2016 at 01:30:19PM +0200, Marcus Müller wrote:
> Now, these microsecond timestamps
> will introduce a /third/ clock into our problems. I can see how the
> control loop converges in case of that clock being both faster than your
> sampling clock and relatively well-behaved, but: is
