On Friday, 1 June 2018 at 18:40:45 UTC, ag0aep6g wrote:
On 06/01/2018 07:00 PM, Xiaoxi wrote:
This prints "3 4 5 6 7 8 9":
import std.range;
import std.algorithm;
import std.stdio;
void main()
{
auto s = "1 2 3 4 5 6 7 8 9";
auto iter = refRange(&s).splitter!(c => c == ' ').drop(2);
On 06/01/2018 07:00 PM, Xiaoxi wrote:
import std.range;
import std.algorithm;
import std.string;
import std.stdio;
void main()
{
auto s = "1 2 3 4 5 6 7 8 9";
auto iter = s.split(" ").drop(2);
// How to find the unconsumed/not-split part of s here?
// i.e. "3 4 5 6 7 8 9" NOT ["3",
On Friday, 1 June 2018 at 17:00:45 UTC, Xiaoxi wrote:
import std.range;
import std.algorithm;
import std.string;
import std.stdio;
void main()
{
auto s = "1 2 3 4 5 6 7 8 9";
auto iter = s.split(" ").drop(2);
// How to find the unconsumed/not-split part of s here?
// i.e. "3 4 5
On 6/1/18 1:00 PM, Xiaoxi wrote:
import std.range;
import std.algorithm;
import std.string;
import std.stdio;
void main()
{
auto s = "1 2 3 4 5 6 7 8 9";
auto iter = s.split(" ").drop(2);
// How to find the unconsumed/not-split part of s here?
// i.e. "3 4 5 6 7 8 9" NOT ["3", "4",
import std.range;
import std.algorithm;
import std.string;
import std.stdio;
void main()
{
auto s = "1 2 3 4 5 6 7 8 9";
auto iter = s.split(" ").drop(2);
// How to find the unconsumed/not-split part of s here?
// i.e. "3 4 5 6 7 8 9" NOT ["3", "4", "5", "6", "7", "8", "9"]
