On Monday, 13 March 2017 at 14:15:05 UTC, Adam D. Ruppe wrote:
On Monday, 13 March 2017 at 14:09:58 UTC, Inquie wrote:
Yeah, so, surely though we can extract the names from the
variable and then supply those like I mentioned?
Yeah, we prolly could, but a simpler thing might be to just use
typ
On Monday, 13 March 2017 at 00:23:36 UTC, ag0aep6g wrote:
On 03/13/2017 01:02 AM, Inquie wrote:
Ok, it doesn't work for appending though ;)
[...]
Tuple!(int, "A", double, "B")[] y;
y ~= tuple(3, 2.5);
Interestingly, this works:
Tuple!(int, "A", double, "B")[] y;
y.length += 1;
y
On Monday, 13 March 2017 at 14:09:58 UTC, Inquie wrote:
Yeah, so, surely though we can extract the names from the
variable and then supply those like I mentioned?
Yeah, we prolly could, but a simpler thing might be to just use
typeof:
Tuple!(int, "A")[] x;
x ~= typeof(x[0])(3
On Monday, 13 March 2017 at 00:51:27 UTC, Adam D. Ruppe wrote:
On Monday, 13 March 2017 at 00:02:12 UTC, Inquie wrote:
I just figured it didn't work in general, but seems to be an
issue with appending.
Oh, it is because of the implicit construction thing, see my
answer here to learn more:
ht
On Monday, 13 March 2017 at 00:02:12 UTC, Inquie wrote:
I just figured it didn't work in general, but seems to be an
issue with appending.
Oh, it is because of the implicit construction thing, see my
answer here to learn more:
http://stackoverflow.com/a/42285015/1457000
You can construct th
On 03/13/2017 01:02 AM, Inquie wrote:
Ok, it doesn't work for appending though ;)
[...]
Tuple!(int, "A", double, "B")[] y;
y ~= tuple(3, 2.5);
Interestingly, this works:
Tuple!(int, "A", double, "B")[] y;
y.length += 1;
y[$ - 1] = tuple(3, 2.5);
On Sunday, 12 March 2017 at 23:55:44 UTC, Adam D. Ruppe wrote:
On Sunday, 12 March 2017 at 23:16:48 UTC, Inquie wrote:
Tuple!(int, "A") x;
x = tuple(3);
fails of course
umm it works for me...
Ok, it doesn't work for appending though ;)
Tuple!(int, "A", double, "B")[] y;
y ~= tuple!("A", "
On Sunday, 12 March 2017 at 23:16:48 UTC, Inquie wrote:
Tuple!(int, "A") x;
x = tuple(3);
fails of course
umm it works for me...
Tuple!(int, "A") x;
x = tuple(3);
fails of course
x = tuple!("A")(3);
Works but specifying the name seems to be redundant. Can we
simplify for the more complex case?
e.g.,
x = tuple!(GetTypleNames!x)(3);
which should then be possible to simplify even further to
x = tuple(3);
or, rather
