On Friday, 3 June 2022 at 12:52:30 UTC, Adam D Ruppe wrote:
On Friday, 3 June 2022 at 12:49:07 UTC, bauss wrote:
I believe it's only true in unicode for utf-32 since all
characters do fit in the 4 byte space they have
Depends how you define "character".
I guess that's true as well, unicode r
On Friday, 3 June 2022 at 12:49:07 UTC, bauss wrote:
I believe it's only true in unicode for utf-32 since all
characters do fit in the 4 byte space they have
Depends how you define "character".
On Thursday, 2 June 2022 at 20:12:30 UTC, Steven Schveighoffer
wrote:
This statement suggests to me that you have an incorrect
perception of a string. A string is a pointer paired with a
length of how many characters after that pointer are valid.
That's it. `str.ptr` is the pointer to the fir
On Thursday, 2 June 2022 at 08:14:40 UTC, Mike Parker wrote:
You've initialized `str` with a string literal. No memory is
allocated for these from the GC. They're stored in the binary,
meaning they're loaded into memory from disk by the OS. So
`str.ptr` points to a static memory location that's
On 6/2/22 1:04 AM, Salih Dincer wrote:
Hi,
Do I misunderstand? A dynamic array is allocated memory according to the
`nextpow2()` algorithm(-1 lapse); strings, on the other hand, don't
behave like this...
```d
string str = "0123456789ABCDEF";
char[] chr = str.dup;
assert(str.length
On Thursday, 2 June 2022 at 08:24:51 UTC, Mike Parker wrote:
And so, `&ts[0]` is the same as `&(*ts.ptr + 0)`, or simply
`ts.ptr`.
That should be the same as `&(*(ts.ptr + 0))`!
On Thursday, 2 June 2022 at 08:14:40 UTC, Mike Parker wrote:
More specifically, it points to the starting address of the
allocated block of memory.
I posted too soon.
Given an instance `ts` of type `T[]`, array accesses essentially
are this:
```d
ts[0] == *(ts.ptr + 0);
ts[1] == *(ts.ptr +
On Thursday, 2 June 2022 at 05:04:03 UTC, Salih Dincer wrote:
Hi,
Do I misunderstand? A dynamic array is allocated memory
according to the `nextpow2()` algorithm(-1 lapse); strings, on
the other hand, don't behave like this...
```d
string str = "0123456789ABCDEF";
char[] chr = str.dup;
