On Monday, 16 March 2015 at 13:33:55 UTC, Robert burner Schadek
wrote:
... from all Unicode characters in an idiomatic D way?
(std.interal.unicode_*)
```
T genUnicodeString(T)(size_t minChars, size_t maxChars)
if(isSomeString!T) {
...
}
```
You'll need two things. A uniform distribution
On Monday, 16 March 2015 at 22:19:52 UTC, Gary Willoughby wrote:
I guess it depends on the encoding?
No the character itself are encoding independent.
Some references:
http://stackoverflow.com/questions/23853489/generate-a-random-unicode-string
This will not work as the caller has to speci
On Monday, 16 March 2015 at 13:33:55 UTC, Robert burner Schadek
wrote:
... from all Unicode characters in an idiomatic D way?
(std.interal.unicode_*)
```
T genUnicodeString(T)(size_t minChars, size_t maxChars)
if(isSomeString!T) {
...
}
```
I guess it depends on the encoding?
Some refe
On Monday, 16 March 2015 at 18:48:29 UTC, bearophile wrote:
Perhaps by rejection? I mean, generating a uint, test if it's a
character and repeat until the result is true.
hm, that must not even terminate.
Robert burner Schadek:
... from all Unicode characters in an idiomatic D way?
Perhaps by rejection? I mean, generating a uint, test if it's a
character and repeat until the result is true.
Bye,
bearophile
... from all Unicode characters in an idiomatic D way?
(std.interal.unicode_*)
```
T genUnicodeString(T)(size_t minChars, size_t maxChars)
if(isSomeString!T) {
...
}
```
