On 2/21/18 6:24 AM, Jiyan wrote:
I think i found my solution: is it __xdtor? :P
Yes, that is the function that will run *recursively* all the
destructors (just __dtor runs the destructor method if you provided
one). But I'd recommend as the others did, using destroy.
-Steve
On Wednesday, 21 February 2018 at 12:07:47 UTC, ketmar wrote:
`p.destroy` will call the dtors for you.
So it is the same function but I prefer to always write it:
.destroy(p);
yes, a leading dot. This ensures you call the top-level destroy
function instead of any members which may not do the
Jiyan wrote:
Hi :),
What i thought was that when i create a struct dynamically i can just
deconstruct it with __dtor lets say:
struct U {...}
struct S {... private U _member;}
S* p;
p = cast(S*)malloc(S.sizeof);
// just run that if it compiles, for simplicity
// we dont use __traits(compil
On Wednesday, 21 February 2018 at 11:12:01 UTC, Jiyan wrote:
Hi :),
What i thought was that when i create a struct dynamically i
can just deconstruct it with __dtor lets say:
struct U {...}
struct S {... private U _member;}
S* p;
p = cast(S*)malloc(S.sizeof);
// just run that if it compiles
Hi :),
What i thought was that when i create a struct dynamically i can
just deconstruct it with __dtor lets say:
struct U {...}
struct S {... private U _member;}
S* p;
p = cast(S*)malloc(S.sizeof);
// just run that if it compiles, for simplicity
// we dont use __traits(compiles, ...)
p.__dt
