---
:wq,
Salvatore.
Sorry, I messed up the formatting
22d21
< #include
48c47
< return bprintf("%d", (temp.value - 27315) / 1E6);
---
> return bprintf("%d", (temp.value - 27315) / 100);
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‐‐‐ Original Message ‐‐‐
On Tuesday, Jun
Hi Suckless
I think there is a problem with the temperature module,
that is, on OpenBSD it only prints one digit,
which by the way doesn't even change (stuck at 5).
By making a small change, it now works properly.
(I also removed stdio.h which looks unnecessary)
22d21
< #include
48c47
<
On Tue, 16 Jun 2020 20:53:34 +0200
Mattias Andrée wrote:
Dear Mattias,
> I'm assuming temp.value i an `int`, as %d is used. The problem was
> probably that `1E6` is actually a `double` rather than an `int`,
> as the whole expression is promoted to `double`, because `bprintf` is
> (I assume) vari
> On 16. Jun 2020, at 22:30, Joerg Jung wrote:
>
>
>> On 16. Jun 2020, at 20:53, Mattias Andrée wrote:
>>
>> I'm assuming temp.value i an `int`, as %d is used. The problem was
>> probably that `1E6` is actually a `double` rather than an `int`,
>> as the whole expression is promoted to `doub
> On 16. Jun 2020, at 20:53, Mattias Andrée wrote:
>
> I'm assuming temp.value i an `int`, as %d is used. The problem was
> probably that `1E6` is actually a `double` rather than an `int`,
> as the whole expression is promoted to `double`, because `bprintf` is
> (I assume) variadic, and the com
I'm assuming temp.value i an `int`, as %d is used. The problem was
probably that `1E6` is actually a `double` rather than an `int`,
as the whole expression is promoted to `double`, because `bprintf` is
(I assume) variadic, and the compiler does not know to change the
cast the expression back to `in
On Tue, 16 Jun 2020 17:55:03 +
messw1thdbest wrote:
Dear messw1thdbest,
> < return bprintf("%d", (temp.value - 27315) / 1E6);
> ---
> > return bprintf("%d", (temp.value - 27315)/100);
I'm really intrigued by that; thanks for sending in this patch! W
