Re: OUStringBuffer

sorry was working with openmeetings and that is in java On Wed, May 8, 2013 at 4:42 AM, Regina Henschel wrote: > Hi Jorge, > > jorge ivan poot diaz schrieb: > >> Hello, >> >> >> I have a doubt, help >> I made this snippet >> >> String abuf = buf.charAt(nLen - 1); >> double ng = ::rtl::

Re: OUStringBuffer

Hi Jorge, jorge ivan poot diaz schrieb: Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( "Is : %i ", ng); I do not meant, that you should call stringToDouble.

Re: OUStringBuffer

Hi, rahul bhola schrieb: take a substring that contains only the last letter and then use Integer.parseInt() to convert it into integer ??? We are in C++ not in Java. Kind regards Regina On Tue, May 7, 2013 at 9:56 PM, jorge ivan poot diaz < ivan.pootd...@gmail.com> wrote: Hello, I hav

Re: OUStringBuffer

take a substring that contains only the last letter and then use Integer.parseInt() to convert it into integer On Tue, May 7, 2013 at 9:56 PM, jorge ivan poot diaz < ivan.pootd...@gmail.com> wrote: > Hello, > > I have a doubt, help > I made this snippet > > String abuf = buf.charAt(nLen - 1); >

Re: OUStringBuffer

Hello, I have a doubt, help I made this snippet String abuf = buf.charAt(nLen - 1); double ng = ::rtl::math::stringToDouble( abuf, '.', ',', NULL, NULL ); printf ( "Is : %i ", ng); But the return value is 0, in theory I want to return the last digit of the string String : world1

Re: OUStringBuffer

Hi Jorge, jorge ivan poot diaz schrieb: thanks, buf.charAt (nLen - 1): this variable has a string as '1' or '2', '3'...'9' as it could change to int, any ideas, please help! I've done this: int ty = buf.charAt(nLen - 1); built well, but the result is not as expected. You should post what you

Re: OUStringBuffer

Herbert Dürr > Hi Jorge, > > like Regina I have a hard time to understand the question. My best guess > is that you have an OUStringBuffer object and need an UniString (aka tool's > String [1]). If that is so you can get it using the UniString constructor > that takes an OU

Re: OUStringBuffer

Hi Jorge, like Regina I have a hard time to understand the question. My best guess is that you have an OUStringBuffer object and need an UniString (aka tool's String [1]). If that is so you can get it using the UniString constructor that takes an OUString argument: UniS

Re: OUStringBuffer

p.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546 Something like this: OUStringBuffer buf( 128 ); buf.append( aName ); buf.append( 4 ); OUString string = buf.makeStringAndClear(); OString oString = rtl::OUStringToOString( string , RTL_TEXTENCODING_ASCII_US ); Substituting aNa

Re: OUStringBuffer

I've already made a concatenation, in this file: http://opengrok.adfinis-sygroup.org/source/xref/aoo-trunk/main/cui/source/tabpages/tpcolor.cxx#546 Something like this: OUStringBuffer buf( 128 ); buf.append( aName ); buf.append( 4 ); OUString string = buf.makeStringAndClear(); OString oS

Re: OUStringBuffer

Hi, jorge ivan poot diaz schrieb: I have doubts about using class OUStringBuffer You should be more specific about your problem. Do you need help in understanding the descriptions in ustrbuf.hxx? Or do you get an compiler error, which do you not understand? Or do you need help about the

OUStringBuffer

I have doubts about using class OUStringBuffer I want to implement this code: x = new OUStringBuffer().append("a").append(4).append("c").toString(); (one example) This snippet, missing something? (A declaration of variables?) I need to include libraries or something? Help me, regards.