Would that not be handled by BigInteger?
I assumed integer literals are treated as BigInter just like float/double
literals are treated as BigDecimals.
Greetings
Angelo
Am 09.12.2019 um 00:51 schrieb Edmond Kemokai :
> I'd read up on the MAX_VALUE doc but didn't see any mention of this
> beha
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B
If you disable the compiler’s primitive optimization, then integer literals
will be BigInteger.
From: Paul King
Sent: Monday, December 9, 2019 11:01 AM
To: Groovy_Developers
Subject: Re: Groovy multiplication
Meta note: This thread is related to the usage of Groovy and best belongs on
the use
On 09.12.19 18:04, Milles, Eric (TR Tech, Content & Ops) wrote:
If you disable the compiler’s primitive optimization, then integer
literals will be BigInteger.
That is not supposed to be the case.
bye blackdrag
