On Fri, 04 Apr 2008 13:54:29 +1100
Rich Healey <[EMAIL PROTECTED]> wrote:
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> Celejar wrote:
> > On Mon, 31 Mar 2008 15:12:33 +1100
> > Rich Healey <[EMAIL PROTECTED]> wrote:
> >
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> >> K
On Mon, 31 Mar 2008 15:12:33 +1100
Rich Healey <[EMAIL PROTECTED]> wrote:
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> Kamaraju S Kusumanchi wrote:
> > My current network configuration is
> >
> > ISP --> wireless router ---> comp1
> > ---> comp2
> >
On Tue, Apr 1, 2008 at 9:16 AM, Kamaraju S Kusumanchi
<[EMAIL PROTECTED]> wrote:
> Rich Healey wrote:
>
> > put them all in the same subnet (ie 192.168.0.128-255) and then nmap -sS
> > - -PN 192.168.0.128/25 | grep [uU][Pp]
>
> What does it mean to say 192.168.0.128/25 ?
/25 indicates the subnet
Rich Healey wrote:
> put them all in the same subnet (ie 192.168.0.128-255) and then nmap -sS
> - -PN 192.168.0.128/25 | grep [uU][Pp]
What does it mean to say 192.168.0.128/25 ?
Instead, I settled on to
sudo nmap -sS -PN 192.168.1.1-255
It seems to be working...
thanks
raju
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Kamaraju S Kusumanchi wrote:
> My current network configuration is
>
> ISP --> wireless router ---> comp1
> ---> comp2
> ---> comp3
>
> The wireless router is wrt54g. The computers might be running Debi
My current network configuration is
ISP --> wireless router ---> comp1
---> comp2
---> comp3
The wireless router is wrt54g. The computers might be running Debian, M$
etc., Is it possible to figure out the number of users and IP addresses of
active c
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