I seem to recall that some years ago ls -l would show the number of hard
links to a file. This may have been on an AIX system. I needed to use this
today on a red hat 8 machine but couldn't figure it out. So I used ls -i
| sort
Am I overlooking a flag to ls that would show me the number of hard
I'm trying to find a project to work on to improve coding skills and
contribute to the community. So I thought that possibly a command line
program would be useful that does similar things as Perl's trim function
and PHP's trim function.
So .. Would it be worth creating a new program, let's call i
I've been perusing the man page for 'ls' and not finding what I'm looking
for. Perhaps I've skipped over it?
I'm looking for a 'ls' option that will list the directory along with the
number of items inside that directory. For instance:
ls -1 --content-count
4 inhumans.2000
12 inhumans.2003
4
This is a creative solution to a problem that I have had for a very long
time. My workaround was to rename files nightly on a cron but this is much
better! Thank you!
On Thu, Apr 15, 2021, 08:17 Carl Edquist wrote:
> On Thu, 15 Apr 2021, Michael Stone wrote:
>
> > I think it's a heck of a lot
'rmdir' is a convenience command to remove empty directories only. So the
answer is no: You'll have to invoke the 'rm' command with options, such as
'-rf', to remove non-empty directories.
On Sat, Jun 25, 2022 at 6:32 AM Бреусов Виталий
wrote:
>Hello! Is it possible to delete a non-empty fo
There are compile time fatal errors/errors/warnings with conftest.c
OS: Debian bookworm
Kernel: x86_64 Linux 6.1.0
Shell: bash 5.2.15
GCC: (Debian 12.2.0-14) 12.2.0
===
Testsuite summary for GNU coreutils 9.1.198-e68b1
=