On Mon, May 3, 2010 at 3:24 PM, Lynn Barton wrote:
> Roland, the application in question uses Core Data. To build a dictionary as
> you suggest, I will need to wait until the array controller loads its
> content, then iterate over all members of the array, putting the property in
> question and
Roland, the application in question uses Core Data. To build a dictionary as
you suggest, I will need to wait until the array controller loads its content,
then iterate over all members of the array, putting the property in question
and the array index into the dictionary. How can I know immedia
Le 28 avr. 2010 à 04:37, Lynn Barton a écrit :
> Newbie question: Consider an array of dictionary objects, all of the same
> class. One of the ivars of that class is an NSString which is unique for each
> instance. Does there already exist a method that will identify the one
> dictionary object
On Apr 27, 2010, at 8:06 PM, Roland King wrote:
> Graham Cox wrote:
>> On 28/04/2010, at 12:37 PM, Lynn Barton wrote:
>>> Newbie question: Consider an array of dictionary objects, all of the same
>>> class. One of the ivars of that class is an NSString which is unique for
>>> each instance. Doe
Graham Cox wrote:
On 28/04/2010, at 12:37 PM, Lynn Barton wrote:
Newbie question: Consider an array of dictionary objects, all of the same
class. One of the ivars of that class is an NSString which is unique for each
instance. Does there already exist a method that will identify the one
dic
On 28/04/2010, at 12:37 PM, Lynn Barton wrote:
> Newbie question: Consider an array of dictionary objects, all of the same
> class. One of the ivars of that class is an NSString which is unique for each
> instance. Does there already exist a method that will identify the one
> dictionary objec
Newbie question: Consider an array of dictionary objects, all of the same
class. One of the ivars of that class is an NSString which is unique for each
instance. Does there already exist a method that will identify the one
dictionary object that has a given value of that ivar, without me having
