Re: NSDivideRect and 64-bit

2009-09-06 Thread Kyle Sluder
On Sep 6, 2009, at 12:37 PM, "James W. Walker" wrote: True. If you look in NSGeometry.h, you find that the constants are still there, but they are #defines instead of enumerated constants in 64 bits. Definitely file a bug about that. They have special tools to deal with all the enums-t

Re: NSDivideRect and 64-bit

2009-09-06 Thread James W. Walker
On Sep 6, 2009, at 12:28 PM, Mitchell Livingston wrote: Under NSRectEdge in the documentation. For example: "NSMinXEdge Specifies the left edge of the input rectangle. The input rectangle is divided vertically, and the leftmost rectangle with the width of amount is placed in slice. Avail

Re: NSDivideRect and 64-bit

2009-09-06 Thread Jens Alfke
On Sep 6, 2009, at 12:28 PM, Mitchell Livingston wrote: Under NSRectEdge in the documentation. For example: "NSMinXEdge Specifies the left edge of the input rectangle. The input rectangle is divided vertically, and the leftmost rectangle with the width of amount is placed in slice. Available

Re: NSDivideRect and 64-bit

2009-09-06 Thread Mitchell Livingston
Under NSRectEdge in the documentation. For example: "NSMinXEdge Specifies the left edge of the input rectangle. The input rectangle is divided vertically, and the leftmost rectangle with the width of amount is placed in slice. Available in Mac OS X v10.0 and later. Not available to 64-bit app

Re: NSDivideRect and 64-bit

2009-09-06 Thread Jens Alfke
On Sep 6, 2009, at 12:01 PM, Mitchell Livingston wrote: I want to use NSDivideRect in my app, but the documentation for NSRectEdge (one of the parameter types) says "Not available to 64- bit applications.". Can I not use this function anymore? Is there an appropriate replacement for the fun

NSDivideRect and 64-bit

2009-09-06 Thread Mitchell Livingston
Hey, I want to use NSDivideRect in my app, but the documentation for NSRectEdge (one of the parameter types) says "Not available to 64-bit applications.". Can I not use this function anymore? Is there an appropriate replacement for the function? Thanks, Mitch _