Thank you very much, it works great.
On Mon, Aug 9, 2010 at 11:23 AM, Meikel Brandmeyer wrote:
> Hi,
>
> On Aug 9, 12:21 pm, Nicolas Oury wrote:
>
>> (zip [a1 an] [b1 bn]) = [[a1 b1] . [an bn]]
>
> (map vector [a1 ... an] [b1 ... bn])
>
> Sincerely
> Meikel
>
> --
> You received th
Hi,
On Aug 9, 12:21 pm, Nicolas Oury wrote:
> (zip [a1 an] [b1 bn]) = [[a1 b1] . [an bn]]
(map vector [a1 ... an] [b1 ... bn])
Sincerely
Meikel
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Dear all,
I can't find a function in the library and don't see any easy way to write it.
I am looking for something like (zip & seqs)
such that (zip [a1 an] [b1 bn]) = [[a1 b1] . [an bn]]
Any function like that or easy way to construct it?
Best regards,
Nicolas.
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