To add to Tassilo's answer, quoting blocks evaluation all the way down. So
even though I don't have the functions foo or bar defined:
user=> '(foo (bar))
(foo (bar))
There's no error, because neither is evaluated.
Chris
On 28 May 2012 18:58, Tassilo Horn wrote:
> Maris writes:
>
> > I have n
Maris writes:
> I have noticed that my functions don't get evaluated if they are
> inside a list:
>
> '({:regex (re-pattern (str root-topic "/price-change//"))
>:metadata (get-metadata :price-change)
>:subscribe nil})
That's because you've quoted (') the list and
I have noticed that my functions don't get evaluated if they are
inside a list:
'({:regex (re-pattern (str root-topic "/price-change//"))
:metadata (get-metadata :price-change)
:subscribe nil})
(get-metadata :price-change) is just a list
Whereas it works if I us
