I'm glad you pointed this out! On stackoverflow everyone was assuming
filter was completely lazy in all cases
On Sunday, May 19, 2013 at 4:54:53 PM UTC+2, Jim foo.bar wrote:
>
> ha! you cheated with iterate...
>
> try this which is closer to the example...
>
> (first (filter odd? (map #(do (prin
On Sun, May 19, 2013 at 4:54 PM, Jim - FooBar(); wrote:
> ha! you cheated with iterate...
>
> try this which is closer to the example...
>
> (first (filter odd? (map #(do (println "realized " %) %) [2 4 6 7 8 9])))
> realized 2
> realized 4
> realized 6
> realized 7
> realized 8
> realized
On Wednesday, 11 February 2009 00:18:53 UTC+8, Jeff Rose wrote:
> Hi,
> Is there a built-in function that will return the first item in a
> collection that matches a predicate? (Something equivalent to Ruby's
> Enumerable#find...) Seems pretty basic, but I can't find it in the docs.
>
> Than
remember the 32-chunked model... :)
Jim
On 19/05/13 15:54, Jim - FooBar(); wrote:
ha! you cheated with iterate...
try this which is closer to the example...
(first (filter odd? (map #(do (println "realized " %) %) [2 4 6 7 8 9])))
realized 2
realized 4
realized 6
realized 7
realized 8
r
ha! you cheated with iterate...
try this which is closer to the example...
(first (filter odd? (map #(do (println "realized " %) %) [2 4 6 7 8 9])))
realized 2
realized 4
realized 6
realized 7
realized 8
realized 9
7
Jim
On 19/05/13 15:31, Cedric Greevey wrote:
On Sun, May 19, 2013 at
On Sun, May 19, 2013 at 10:06 AM, Jim - FooBar(); wrote:
> no need to traverse the entire seq with 'filter' if you only want the
> 1st match...
>
Pretty sure filter is lazy.
user=> (first (filter odd? (map #(do (println "realized " %) %) (iterate
inc 0
realized 0
realized 1
1
user=>
--
Try this
user> (first (drop-while even? [2 4 6 7 8 10]))
7
19.05.2013, 23:06, "Jim - FooBar();" :
> no need to traverse the entire seq with 'filter' if you only want the 1st
> match...
>
> (some #(when (odd? %) %) [2 4 6 7 8 9])
> => 7
>
> Jim
>
> On 19/05/13 13:42, Thumbnail wrote:
>
>> ... or
no need to traverse the entire seq with 'filter' if you only want the
1st match...
(some #(when (odd? %) %) [2 4 6 7 8 9])
=> 7
Jim
On 19/05/13 13:42, Thumbnail wrote:
... or just (comp first filter)
((comp first filter) odd? [2 4 6 7 8 9])
=> 7
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... or just (comp first filter)
((comp first filter) odd? [2 4 6 7 8 9])
=> 7
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Hi,
Am 10.02.2009 um 18:00 schrieb Jeff Rose:
Oh cool! I hadn't thought about this aspect of laziness before. I
can
see there is some zen here that is worth exploring...
Many ways to Rome:
(first (drop-while (complement predicate) coll))
:)
Sincerely
Meikel
smime.p7s
Description: S/
Oh cool! I hadn't thought about this aspect of laziness before. I can
see there is some zen here that is worth exploring...
Thanks Mark and Stuart.
-Jeff
Mark Fredrickson wrote:
> Filter is lazy:
>
> http://clojure.org/api#toc228
>
> So you can implement find-first as (first (filter pred col
On Feb 10, 11:18 am, Jeff Rose wrote:
> Is there a built-in function that will return the first item in a
> collection that matches a predicate? (Something equivalent to Ruby's
> Enumerable#find...) Seems pretty basic, but I can't find it in the docs.
Hi, Jeff, here's how I do it:
user> (de
Filter is lazy:
http://clojure.org/api#toc228
So you can implement find-first as (first (filter pred coll))
-M
On Feb 10, 2009, at 10:19 AM, Jeff Rose wrote:
>
> Well, in case someone else needs the same function and it isn't built-
> in, here's what I'm using in the meantime. (Based off of
Well, in case someone else needs the same function and it isn't built-
in, here's what I'm using in the meantime. (Based off of the some
function that comes in core...)
(defn find-first [pred coll]
(when (seq coll)
(if (pred (first coll))
(first coll)
(recur pred (rest coll
Hi,
Is there a built-in function that will return the first item in a
collection that matches a predicate? (Something equivalent to Ruby's
Enumerable#find...) Seems pretty basic, but I can't find it in the docs.
Thanks,
Jeff
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