; > user=> (time (filter identity [ nil 1 2 nil 4]))
> > > > "Elapsed time: 0.053219 msecs"
> > > > (1 2 4)
> > > >
> > > > user=> (time (remove nil? [ nil 1 2 nil 4]))
> > > > "Elapsed time: 0.065092 msecs&quo
cs"
> > > (1 2 4)
> > >
> > > user=> (time (remove nil? [ nil 1 2 nil 4]))
> > > "Elapsed time: 0.065092 msecs"
> > > (1 2 4)
> > >
> > > Choose the flavor your prefer...
> > >
ote:
>
> > user=> (time (filter identity [ nil 1 2 nil 4]))
> > "Elapsed time: 0.053219 msecs"
> > (1 2 4)
> >
> > user=> (time (remove nil? [ nil 1 2 nil 4]))
> > "Elapsed time: 0.065092 msecs"
> > (1 2 4)
> >
> >
2:37:16 AM UTC+1, Luc wrote:
>>
>> user=> (time (filter identity [ nil 1 2 nil 4]))
>> "Elapsed time: 0.053219 msecs"
>> (1 2 4)
>>
>> user=> (time (remove nil? [ nil 1 2 nil 4]))
>> "Elapsed time: 0.065092 msecs"
>> (1 2 4)
il 1 2 nil 4]))
> "Elapsed time: 0.065092 msecs"
> (1 2 4)
>
> Choose the flavor your prefer...
>
> Luc P.
>
> Glen Rubin > wrote ..
> > What is the fastest way to remove nils from a sequence?
> >
> > I usually use the filter function, but I see
On Thu, Nov 18, 2010 at 10:47 AM, Glen Rubin wrote:
> So, it seems the way I was removing nils using filter was already the
> best way. still nice to learn about the keep fn. thx!
I don't know if we can conclude that yet. It seems to be fastest on
one system with one combination of Java version
So, it seems the way I was removing nils using filter was already the
best way. still nice to learn about the keep fn. thx!
On Nov 17, 8:38 pm, Ken Wesson wrote:
> On Wed, Nov 17, 2010 at 7:55 PM, Robert McIntyre wrote:
> > So, just to be clear,
>
> > user> (def nil-seq (doall (interleave (rep
On Wed, Nov 17, 2010 at 7:55 PM, Robert McIntyre wrote:
> So, just to be clear,
>
> user> (def nil-seq (doall (interleave (repeat 1e5 nil) (repeat 1e5
> "whatever"))) )
> #'user/nil-seq
>
> user> (time (doall (keep identity nil-seq)))
> "Elapsed time: 122.485848 msecs"
>
> user> (time (doall (remo
)))
> "Elapsed time: 0.044 msecs"
> ()
> user> (time (doall (remove nil? (repeat 100 nil
> "Elapsed time: 772.469 msecs"
> ()
>
> -Steve
>
>
>
>
>
>>
>> On Nov 16, 4:48 pm, Glen Rubin wrote:
>>> What is the fastest way to
r YMMV
You're not timing the execution, just the construction of a lazy seq:
user> (time (remove nil? (repeat 100 nil)))
"Elapsed time: 0.044 msecs"
()
user> (time (doall (remove nil? (repeat 100 nil
"Elapsed time: 772.469 msecs"
()
-Steve
>
>
Re-oups, Clojure 1.0 to 1.2 upgrade glitch :)
Mark Engelberg wrote ..
> (keep identity l) is preferable to (filter identity l)
>
> --
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> To post to this group, send email to clojure@googlegroups.com
>
Oups.. :)
Stuart Campbell wrote ..
> On 17 November 2010 12:37, wrote:
>
> > user=> (time (filter identity [ nil 1 2 nil 4]))
> > "Elapsed time: 0.053219 msecs"
> > (1 2 4)
> >
> > user=> (time (remove nil? [ nil 1 2 nil 4]))
> > "Elapsed time: 0.065092 msecs"
> > (1 2 4)
> >
> > Choose the fla
(keep identity l) is preferable to (filter identity l)
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On 17 November 2010 12:37, wrote:
> user=> (time (filter identity [ nil 1 2 nil 4]))
> "Elapsed time: 0.053219 msecs"
> (1 2 4)
>
> user=> (time (remove nil? [ nil 1 2 nil 4]))
> "Elapsed time: 0.065092 msecs"
> (1 2 4)
>
> Choose the flavor your prefer...
>
> Luc P.
>
Those aren't exactly equiv
user=> (time (remove nil? (repeat 100 nil)))
"Elapsed time: 0.079312 msecs"
()
user=> (time (filter identity (repeat 100 nil)))
"Elapsed time: 0.070249 msecs"
()
Seems like filter is a bit faster, however YMMV
On Nov 16, 4:48 pm, Glen Rubin wrote:
> What
user=> (time (filter identity [ nil 1 2 nil 4]))
"Elapsed time: 0.053219 msecs"
(1 2 4)
user=> (time (remove nil? [ nil 1 2 nil 4]))
"Elapsed time: 0.065092 msecs"
(1 2 4)
Choose the flavor your prefer...
Luc P.
Glen Rubin wrote ..
> What is the fastest way t
What is the fastest way to remove nils from a sequence?
I usually use the filter function, but I see there are other functions
like remove that should also do the trick.
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