Wow, that some function is just what I'd expect from Clojure, simple,
straightforward, elegant. How did I miss it?
Thanks all.
Tuba
On Jul 18, 11:00 pm, David Nolen wrote:
> On Tue, Jul 19, 2011 at 12:48 AM, Tuba Lambanog
> wrote:
>
> > Hi,
> > I'm clear on what I want ;) (something new to me),
On Tue, Jul 19, 2011 at 12:48 AM, Tuba Lambanog wrote:
> Hi,
> I'm clear on what I want ;) (something new to me), but I'm not clear on how
> to get there. I'd like to compare str1 and str2, if at least one of the
> letters in str1 is in str2. I'm thinking that if I can convert str1 and str2
> to s
(some (set str1) str2)
will give you what you want..
Sunil
On Tue, Jul 19, 2011 at 10:06 AM, Tuba Lambanog wrote:
> (thank-you "Sean A Corfield)
>
>
> On Mon, Jul 18, 2011 at 10:29 PM, Sean Corfield wrote:
>
>> On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog
>> wrote:
>> > (set "abc")
>> > give
In that case you don't need to convert to a symbol...
(set "abc") should be fine...
Using set intersection, something like this is probably what you're looking
for...
(use 'clojure.set)
(if (empty? (intersection (set "abc") (set "cde"))) false true))
I'm sure there's other (better) ways though
Hi,
I'm clear on what I want ;) (something new to me), but I'm not clear on how
to get there. I'd like to compare str1 and str2, if at least one of the
letters in str1 is in str2. I'm thinking that if I can convert str1 and str2
to sets, then I can use the set intersection operation. It probably do
(thank-you "Sean A Corfield)
On Mon, Jul 18, 2011 at 10:29 PM, Sean Corfield wrote:
> On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog
> wrote:
> > (set "abc")
> > gives me #{\a \b \c}.
> > I'm expecting instead: #{a b c}
>
> (set (map "abc"))
>
> (set (map str "Tuba Lambanog"))
> --
> Sean A Corf
I'm with Benjamin despite my last post...
On 19/07/2011, at 2:31 PM, Benjamin Esham wrote:
> Tuba Lambanog wrote:
>
>> Tuba Lambanog wrote:
>>
>>> Hello, My apologies for this newbie question. I couldn't find a way to
>>> convert a string to a set, thus:
>>>
>>> "abc" => #{a b c}
>>
>> (set "a
On 19/07/2011, at 2:29 PM, Sean Corfield wrote:
> On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog
> wrote:
>> (set "abc")
>> gives me #{\a \b \c}.
>> I'm expecting instead: #{a b c}
>
> (set (map "abc"))
>
> (set (map str "Tuba Lambanog"))
This will produce #{"a" "b" "c"}
I think
(set (map
Tuba Lambanog wrote:
> Tuba Lambanog wrote:
>
> > Hello, My apologies for this newbie question. I couldn't find a way to
> > convert a string to a set, thus:
> >
> > "abc" => #{a b c}
>
> (set "abc") gives me #{\a \b \c}. I'm expecting instead: #{a b c}
Hi Tuba,
Are you quite sure that #{\a
On Mon, Jul 18, 2011 at 9:17 PM, Tuba Lambanog wrote:
> (set "abc")
> gives me #{\a \b \c}.
> I'm expecting instead: #{a b c}
(set (map "abc"))
(set (map str "Tuba Lambanog"))
--
Sean A Corfield -- (904) 302-SEAN
An Architect's View -- http://corfield.org/
World Singles, LLC. -- http://worldsin
Hi,
(set "abc")
gives me #{\a \b \c}.
I'm expecting instead: #{a b c}
But thanks,
Tuba
On Mon, Jul 18, 2011 at 9:50 PM, Tuba Lambanog wrote:
> Hello,
> My apologies for this newbie question. I couldn't find a way to
> convert a string to a set, thus:
>
> "abc" => #{a b c}
>
> Thanks.
> tuba
>
> -
(set "abc") will do it...
On Tue, Jul 19, 2011 at 9:20 AM, Tuba Lambanog wrote:
> Hello,
> My apologies for this newbie question. I couldn't find a way to
> convert a string to a set, thus:
>
> "abc" => #{a b c}
>
> Thanks.
> tuba
>
> --
> You received this message because you are subscribed to t
Hello,
My apologies for this newbie question. I couldn't find a way to
convert a string to a set, thus:
"abc" => #{a b c}
Thanks.
tuba
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