Also keep in mind, that in (.something obj), the compiler doesn't see a
call to .method, but the whole thing is desugared into a call to the dot
form: (. obj something). Since . is a special form, it is always defined.
So when trying to analyze a call to the dot special form, keep in mind that
the
Hi,
as others said: to check that a protocol function exists you can use
resolve as with every other function.
If you wanted to know, whether a type participates in a protocol directly,
you would check whether it implements the protocol's interface .
user=> (defprotocol Foo (foo [this]))
Foo
u
>
> What should I be using to check that the symbol .firstName and
> .fullName are defined in the current scope?
>
"fullName" is easier because it gets interned in the current namespace:
user=> (ns-interns 'user)
{fullName #'user/fullName, ->Person #'user/->Person,
On Wed, Feb 29, 2012 at 5:12 PM, Frank Wilson wrote:
> Hi,
>
> The behaviour of resolve for named functions seems pretty clear to me:
>
> (resolve 'xyz)
>
> returns nil (when xyz has not been defined).
>
> and
>
> (defn xyz [x] 1)
>
> (resolve 'xyz)
>
> returns #'user/xyz (when xyz is defined)
>
Hi,
The behaviour of resolve for named functions seems pretty clear to me:
(resolve 'xyz)
returns nil (when xyz has not been defined).
and
(defn xyz [x] 1)
(resolve 'xyz)
returns #'user/xyz (when xyz is defined)
However if I try to define types:
(defprotocol Named
(fullName [Named]))
