> Not the right answer. I tried to use the apply function with no
> success.
> How can I wrap the expression inside a function.
Why not use partition and interleave?
user> (partition 2 (interleave [:a :b] [:c :d]))
((:a :c) (:b :d))
U
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Hi,
the use of a apply should work. Also note the (partial conj []) is not
necessary. vector works as well.
user=> (defn columns [& xs] (apply map vector xs))
#'user/columns
user=> (columns [:a :b] [:c :d])
([:a :c] [:b :d])
Sincerely
Meikel
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Given a list of vectors, I want to return a list of vector whose
elements are grouped by index.
For example: Given [:a :b] [:c :d] => [:a :c] [:b :d]
For this, I wrote the expression
(map (partial conj []) [:a :b] [:c :d])
=> [:a :c] [:b :d]
It returned the right answer. Now I want wrap the above
