Thanks for answer my question.
On Saturday, December 26, 2015 at 10:59:51 PM UTC+8, Leif wrote:
>
> Hi, Mian Pao.
>
> When you call the macro te, a is bound to the *symbol* 'print, not the
> *function* print. So, what the ~(a b c) form is doing is calling the
> symbol 'print as a function:
> ('
Hi, Mian Pao.
When you call the macro te, a is bound to the *symbol* 'print, not the
*function* print. So, what the ~(a b c) form is doing is calling the
symbol 'print as a function:
('print 1 '(2 3)) => '(2 3)
This is because symbols and keywords implement the function interface, and
the cal
Hi, Mian Pao.
When you call the macro te, a is bound to the *symbol* 'print, not the
*function* print. So, what the ~(a b c) form is doing is calling the
symbol 'print as a function:
('print 1 '(2 3)) => '(2 3)
This is because symbols and keywords implement the function interface, and
the cal
