java to the rescue!
Thanks to all for your suggestions
Scott
On Mar 13, 3:45 pm, Michał Marczyk wrote:
> On 12 March 2010 23:26, Scott wrote:
>
> > How do I write a function 'bit' that converts an integer to binary
> > representation:
>
> > (bit 0) -> 2r0
> > (bit 1) -> 2r1
> > (bit 2) -> 2r10
On 12 March 2010 23:26, Scott wrote:
> How do I write a function 'bit' that converts an integer to binary
> representation:
>
> (bit 0) -> 2r0
> (bit 1) -> 2r1
> (bit 2) -> 2r10
> (bit 3) -> 2r11
I understand that you want a way to obtain a string representation of
a number in binary. I think you
Yes, yes - that's what I mean. Things get a little muddled on Friday
afternoon. The reader converts the representation, and there's not a
fast/easy way to get the original representation back and manipulate it.
On Mar 12, 2010, at 4:53 PM, Kevin Downey wrote:
uh, you are confusing represe
uh, you are confusing representation of the thing with the thing.
Integers don't have bases, bases are used when displaying them. The
reader does not convert a "2r0" to a "base-10 Integer value" because
there is no such thing.
On Fri, Mar 12, 2010 at 4:23 PM, Brendan Ribera
wrote:
> Whenever you
Whenever you use the "2r0" format, the reader automatically converts it to
its base-10 Integer value. This transformation happens at the reader level
right now -- check out the 'matchNumber' method in LispReader.java for
details. So (as far as I can tell) this means that there is no standalone
bina
