Ah, for some reason, I had it in my head that the value found in the map
was the *last* argument passed to the function.
This behavior makes a lot more sense now. Thanks for the clarification!
On Thursday, May 29, 2014 11:00:58 AM UTC-6, Stuart Fehr wrote:
>
> I am not sure if this is considered
it is expected behavior, because update-in calls the supplied function with
the value it finds in the map as the first argument, so your first call
ends up being
(remove [1 2 3] #{2})
Since ([1 2 3] 2) = 3 and is truthy, the result is ().
In your second case you're using (partial remove #{2}), s
