Thanks, Alan. It is more general solution which also works for keys
that are not keywords
user=> (map {"a" 1 "b" 2 "c" 3} [ "a" "b"])
(1 2)
On Dec 1, 5:02 pm, Alan Malloy wrote:
> I usually use juxt, but a more correct/robust solution is to use map,
> with the lookup-map as the function:
>
> (map
I usually use juxt, but a more correct/robust solution is to use map,
with the lookup-map as the function:
(map {:foo 1 :bar 2 :baz 0} [:foo :bar])
On Dec 1, 12:26 pm, Ulises wrote:
> How about using juxt:
>
> sandbox> ((juxt :foo :bar) {:foo 1 :bar 2 :baz 0})
> [1 2]
> sandbox>
>
> This only wo
Thanks, works in my case.
On Dec 1, 3:26 pm, Ulises wrote:
> How about using juxt:
>
> sandbox> ((juxt :foo :bar) {:foo 1 :bar 2 :baz 0})
> [1 2]
> sandbox>
>
> This only works, however, if you use keywords for keys (as they are
> functions themselves).
>
> U
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((juxt :foo :bar) {:foo 1 :bar 2 :baz 3})
juxt to the rescue
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How about using juxt:
sandbox> ((juxt :foo :bar) {:foo 1 :bar 2 :baz 0})
[1 2]
sandbox>
This only works, however, if you use keywords for keys (as they are
functions themselves).
U
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