Armando, Nate and Panduranga
Many thanks for the answers.
Regards,
Alex
2012/8/28 Nate Young
> On Thu, Aug 23, 2012 at 11:22 AM, Alexsandro Soares
> wrote:
> > Can you provide the code for this?
> Certainly.
>
> The parser's current source position is stored in the InputState
> record's `p
On Thu, Aug 23, 2012 at 11:22 AM, Alexsandro Soares
wrote:
> Can you provide the code for this?
Certainly.
The parser's current source position is stored in the InputState
record's `pos` field. That field is a SourcePos record consisting of
the current line and column position. Most parsers, howe
Alexsandro,
I don't know about Parsatron, but Parse-EZ (
https://github.com/protoflex/parse-ez) provides the 'line-pos' function
that returns the line and column info.
Here is the equivalent code for your example using Parse-EZ:
--
(use 'protoflex.parse)
(defn anbn []
(let [as (re
Alexsandro,
I don't know about Parsatron, but Parse-EZ (
https://github.com/protoflex/parse-ez) provides the 'line-pos" function
that returns [line# column#] vector.
Here is the equivalent code for your example using Parse-EZ:
(use 'protoflex.parse)
(defn anbn []
(let [as (regex
Hi Nate,
Can you provide the code for this?
Thanks,
Alex
2012/8/23 Nate Young
> On Thu, Aug 23, 2012 at 9:24 AM, Alexsandro Soares
> wrote:
> > Ok. Thanks for the answer.
> >
> > Is there any way to get the line and column?
> The Parsatron doesn't have any builtin facilities for extracting li
On Thu, Aug 23, 2012 at 9:24 AM, Alexsandro Soares
wrote:
> Ok. Thanks for the answer.
>
> Is there any way to get the line and column?
The Parsatron doesn't have any builtin facilities for extracting line
numbers from tokens, you'd have to keep track of the number of newline
characters your parse
Ok. Thanks for the answer.
Is there any way to get the line and column?
For example, in this parser
(defparser ident []
(>> (letter) (many (either (letter) (digit)
I want the token and the initial line and column. How can I change this
code?
Cheers,
Alex
--
You received this message b
pL first tries anbn: many parses zero \a's; then times has to parse zero
\b's; and the parser returns the concatenation of two empty lists. An empty
list isn't a failure as far as the parser either is concerned, so it won't
try xdny in that case.
On Wednesday, August 22, 2012 5:38:56 PM UTC-7,
Hi all,
I'm using the Parsatron library to build parser combinators. I have the
following definition:
(defparser anbn []
(let->> [as (many (char \a))
bs (times (count as) (char \b))]
(always (concat as bs
(defparser xdny []
(let->> [ds (between (char \x) (char \y)
