Thanks Jane!
I will go with 2048 PG.
Thanks,
Gagan
On Thu, May 1, 2025 at 12:49 PM Janne Johansson wrote:
> Den tors 1 maj 2025 kl 09:12 skrev gagan tiwari
> :
> >
> > HI Janne,
> > Thanks for the explanation.
> >
> > So, using all 10X15 Disks on
Den tors 1 maj 2025 kl 09:12 skrev gagan tiwari
:
>
> HI Janne,
> Thanks for the explanation.
>
> So, using all 10X15 Disks on 7 OSD nodes. Number PG will be :-
>
> ( 10X7X100 ) / 6 = 1166.666 nearest power of 2 is 2028.
>
> So, I will need to set 2028 placement groups. With
HI Janne,
Thanks for the explanation.
So, using all 10X15 Disks on 7 OSD nodes. Number PG will be :-
( 10X7X100 ) / 6 = 1166.666 nearest power of 2 is 2028.
So, I will need to set 2028 placement groups. With 2028 PG , three will be
12,168 pieces to be spread out on 70
OSDs
> Hi Guys,
> I have 7 OSD nodes with 10X15T NVME disk on each OSD node.
>
> To start with , I want to use only 8X15T disk on each osd node and keep
> 2X15 disk spare in case of any disk failure and recovery event.
>
> I am going to use the 4X2 EC CephFS data pool to store data.
>
>
