In the $CHTML/twinning.html it tries to explain:
From the table:
# All *P2i3* and related *2i3* space groups:
(h,k,l) already equivalent to (-h,-k,l) so we only need to check:
real axes: (a,b,c) and (b,a,-c)
reciprocal axes:(a*,b*,c*) and (b*,a*,-c*)
/i.e./ rein
Dear 'old' crystallographers,
During one case of structure solution, the data processing programs output
incorrect space group-primitive cubic P4132, which later found out that the
correct one should be face centerd cubic f23. This problem was caused by
perfect twinning.
Now I'd like to invite
