Hi Pete,
A couple of observations with this. I found when doing cell refinement
with Mosflm setting a conservative resolution limit *was* very helpful
in making sure that the refinement was stable. But then switching back
to the full detector area for integration was fine after that. However
- and
Hi Graeme,
That's interesting. When I looked at this (and I would say I looked
reasonably carefully) I found it only made a difference in the scaling
- integrating across the whole area was fine. However, I would expect
to see a difference, and likely an improvement, in scaling only the
data you
Hi Tim,
That's interesting. When I looked at this (and I would say I looked
reasonably carefully) I found it only made a difference in the scaling
- integrating across the whole area was fine. However, I would expect
to see a difference, and likely an improvement, in scaling only the
data you want
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Dear Abd Ghani,
The method described by Graeme is how the resolution can be delimited
artificially.
If you want to get the best from your data, determine the resolution
limit of your data e.g. with pointless (I/sigI > 2.0 is a good marker)
and reproce
... presuming of course the automated software got this resolution limit right.
If for whatever reason you would like to cut the limit mtzutils will
do this nicely:
mtzutils hklin blah_free.mtz hklout blah_lower.mtz << eof
resolution 1.8
eof
(say) - I am sure there are other ways within the suit
Qs
1) Why do you want to limit your data?
Most applications allow you to only use a specified sub-set - see GUI tasks
for "resolution limits".
In general you may want to run moleculer replacement or exptl phasing at a
limited resolution, but for refinenement or phase extension it is good to
hello everyone,
I am new in this bulletin board. I would like to know on how to cut my
resolution in my datasets that have been processed/produced in diamond light
source. In my processed directory, I found there are 3 files (free.mtz,
scaled.sca and unmerged.sca). May I know which one can be u