I think you have just found a symmetry equivalent of your original
structure solution.
In P6122 there are 12 possible symmetry operators to choose from - only
one of which will be the identity (equivalent to alpha=beta=gamma=0)
One certainly will have alpha or gamma = 180, and beta 0, equivalen
Dear Michele,
I think your MR solution is on a different allowed
origin - that's all
Ciao
Pietro
--
Pietro Roversi
Sir William Dunn School of Pathology, Oxford University
South Parks Road, Oxford OX1 3ER, England UK
Tel. 0044-1865-275385
Dear Michelle,
this is not strange at all. You simply have
a MR solution that refers to a different origin.
You cannot display the original model plus the
MR solution in the same coordinate system (with
respect to the same origin). Of
course they clash.
Greetings
Marius
> Dear all,
>
> I refin
Dear all,
I refined a protein structure in the space group P6(1)22, with one copy in the
asymmetric unit, resolution ~1.8 A, Rwork=0.20, Rfree=0.22.
Then I tried to feed Phaser (version 1.3.3) with this structure. It found
quickly a very prominent solution, but the first euler angle is 180 inst
