You could do http://www.application.com/message/add/contract:1 using
named parameters.
Or setup a route for www.application.com/contract/1/message/add
On Dec 28, 11:09 pm, otisjs01 wrote:
> OK, so I'm asking lots of questions today...but I really want to
> learn! :)
>
> Anyway, I'm trying to cre
Thanks John. Option B does indeed work - sort of! It returns a list of
location types with a count of their locations, but only where there
is a location. In other words, it does not give me the location types
that do not have have any locations.
Any more ideas - anyone?
On Dec 29, 12:35 pm, John
Hi,
I am out the office until the 14th of January. If you require urgent
assistance then please contact p...@citadelsecure.com or call him on 07890
592198 - otherwise I will answer your email on my return.
Regards
Jim
Check out the new CakePHP Questions site http://cakeqs.org and help o
Couldn't you just use app_model.php to make the data available to all
your models?
On Dec 28, 2:18 am, dyutiman wrote:
> Hi Nabil,
> thanks for your reply and suggestion. It'll really help.
> I thought about getting the cookie value in controller and pass it to
> model. But for this I have to r
OK, thanks. And it makes sense to test it in the test case for a
controller that uses it, right?
cheers
Lorenzo
edwingt wrote:
> You have to includ it in the vendors directory and load it as
> App::import
> More info here http://book.cakephp.org/view/538/Loading-Vendor-Files
>
> On 29
You have to includ it in the vendors directory and load it as
App::import
More info here http://book.cakephp.org/view/538/Loading-Vendor-Files
On 29 dic, 10:53, Lorenzo Bettini wrote:
> Hi
>
> I've just started using cakephp and I'm porting an older application.
>
> I need to use a bibtex parser,
I have a model object called "ImpresorasProducto" that belongs to a
NxM relationship table impresoras_productos.
When I'm in "ImpresorasProductosController" and debug the model object
it prints this:
ImpresorasProducto Object
(
[name] => ImpresorasProducto
[belongsTo] => Array
(
Hi
I've just started using cakephp and I'm porting an older application.
I need to use a bibtex parser, so I was wondering "where to put" such
parser... in a model? in a component? what else?
Or is it still good to use it as a standalone php code? In that case,
how can I use it, say, inside
as i said
it might work in most cases where you dont have the folders in
between.
but even if it works due to the virtual host pointing it is still not
correct
On 29 Dez., 15:42, John Andersen wrote:
> Ok, I will have to try it out later!
> I have Apache virtual host pointing to my applications
Hi,
I am out the office until the 14th of January. If you require urgent
assistance then please contact p...@citadelsecure.com or call him on 07890
592198 - otherwise I will answer your email on my return.
Regards
Jim
Check out the new CakePHP Questions site http://cakeqs.org and help o
Ok, I will have to try it out later!
I have Apache virtual host pointing to my applications webroot, which
is why I don't see a problem, even if I change the virtual host to
point to the application directory or the root directory.
Thanks for the info, enjoy,
John
On Dec 29, 4:38 pm, euromark
I've been using John's solution in many places and it seems to work
correcly...
John Andersen wrote:
> Sorry, I just tried to move my document root away from the application
> webroot, nothing was added to the url, it looks exactly like it always
> do! Can you give an example of when the url will
usually you dont need to change the $uses array!
they should be linked inside the model anyway - with hasMany and
belongsTo relations
this way you should refer to them inside the controller:
$this->Image->foo()
$this->Image->Article->bar()
On 29 Dez., 14:40, Renato de Freitas Freire
wrote:
> i
i meant "array or string" :)
On 29 Dez., 13:51, John Andersen wrote:
> Sorry, I just tried to move my document root away from the application
> webroot, nothing was added to the url, it looks exactly like it always
> do! Can you give an example of when the url will include additional
> folders?
>
the url may either be an array or a link
well its fairly easy
if you have www.domain.de/myapp/... via mod_rewrite mapped to /myapp/
webroot/
if you use $html->url() or link() you get /myapp/controller/action
now - include this link in the $html->link() again, you get /myapp/
myapp/controller/act
I'm using eclipse, but it doesn't seem to work on ctp files, and in most
of other cases it is not able to autocomplete when using cake...
euromark wrote:
> and by the way
> you really should use the right IDE. a good PHP Editor will make it
> easy for you to look it up.
> i - for example - use th
Here's a new tutorial that's a bit more relevant
http://foldifoldi.com/news/?p=466
On Dec 25, 9:15 am, foldiman wrote:
> Andrew,
> It sounds like you want to use a join in yourpaginationquery. If you
> have set up your model relationships, the joins may happen
> automagically. However, you c
in your controller, you can set as many models as you want to use.
like:
var $uses = arraya('Image','Article');
to save data in each model, you can just access it like:
$this->Image->save($your-data-var);
$this->Article->save($your-other-data-var);
if there is a way to make your article model s
Hi Guys,
How's going?
so, I trying to figure out the following scenario:
2 models:
- articles
- images
on my images table i have a column id_article.
1 view:
- article + the field to upload 1 image.
Problem:
HOw to store the image using article_model and pass the data to
images_model?
tk
Sorry, I just tried to move my document root away from the application
webroot, nothing was added to the url, it looks exactly like it always
do! Can you give an example of when the url will include additional
folders?
In your example, what is the content of the $url variable?
Enjoy,
John
On
A correction, example A gives the author with all the articles, but
the article count is 1 (one) - so no luck using that!
Enjoy,
John
[snip]
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
You received this message because you a
Hi Jeremy,
I tried to play with your problem, using my own models and came up
with this:
Example A - gives the same issue as you have - unknown column!
$results = $this->Author->find(
'all',
array(
'contain' => array('Article'),
'conditions' => arra
and by the way
you really should use the right IDE. a good PHP Editor will make it
easy for you to look it up.
i - for example - use the phpdesigner 7 which is able to include the
whole core libraries
if i move my mouse over the parameters of $html->link() i am able to
see its parameter names + d
actually its even way easiert!
$html->link($url, TRUE)
does the trick
the above solution from john might even be wrong in some cases
(if you're not at the top level of your domain, it adds the folders to
the webroot twice...)
On 29 Dez., 12:00, Lorenzo Bettini wrote:
> Hey thanks, that's ex
Hi John - thanks for the reply. No luck, I'm afraid - I get the same
result.
I have simplified my example so I can focus in on what's not right:
$results = $this->LocationType->find(
'all',
array(
'recursive' => 2,
'contain' => array(
Hey thanks, that's exactly what I needed!
I had searched for it in the HtmlHelper but I hadn't found it since it's
an inherited method :)
cheers
Lorenzo
John Andersen wrote:
> Use the html helpers url method to create the full url for the html
> helpers link method, as:
>
> echo $html-
I feel the same way sometimes. It is tempting to use model methods as
$record->method() in a way similar to an object-based ORM (e.g. Rails,
where class methods are used for finding and instance methods are used
for record manipulation).
But the way Cake works it is a bit dangerous and I would rec
Hmm, I see that there are more issues - reading the last piece of your
post - what are your models, because in the beginning you specify User
and Copy and in the last part, you specify User and Friendship - so I
am confused :)
To use debug(), turn on debug in your configuration - see your /app/
co
Try first just to define your hasMany relationship between the User
and the Copy models as:
var $hasMany = array('Copy');
Your other issue is that the condition for the find statement is not
the word "condition" but "conditions" (plural) :)
Enjoy,
John
On Dec 29, 10:55 am, Jaimon wrote:
Ok, I will give it a try :)
The first thing I observe is that the group statement does not include
all the non-grouped columns, which it should, like:
'group' => array(
'LocationType.id',
'LocationType.name',
'LocationType.parent_id',
'ParentLocationType.id',
'ParentLocationType.nam
Use the html helpers url method to create the full url for the html
helpers link method, as:
echo $html->link('TEST LINK', $html->url('/advances/forward', true));
Enjoy,
John
On Dec 29, 11:07 am, Lorenzo Bettini wrote:
> Hi
>
> with the Html and Form helper it's already easy to create absolu
Any takers for this please?
On Dec 23, 6:01 am, Jeremy Burns wrote:
> I have progressed a little with this, but am still struggling. I seem
> to get hung up on the simplest of things with CakePHP, which is so
> frustrating. I am prepared to be humiliated with an equally simple
> answer to my prob
Hi
with the Html and Form helper it's already easy to create absolute links
(starting from the root of the site), but I'd need to create links that
also include the address of the site (starting with http://).
This is needed since the output of the cakephp site should also be
included in other
Thanks for all the information!
Let's see how testing is in the next release, and in particular the
documentation; as for proposing an alternative in the book I guess I
should file a ticket, right?
For the moment I'm testing controllers' actions the "hard way" :)
cheers
Lorenzo
nurvzy
OK, i am little bit lost...
i am pretty new to php, and i am trying to use cakePHP for my web-
site.
my db is composed of two tables:
- users with user_id, name columns
- copies with copy_id, copy_name, user_id (as foreign key to users)
columns.
and i have the matching cakePHP elements:
- Us
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