Nevermind...lol too late to be coding...
For some reason the user_id column in the departments_users table had
been set as a primary key. I'm not exactly sure why, but who knows
maybe I totally bailed and set a primary key flag somewhere along the
line.
Everything is working though.
On 4 Oct, 0
I have a situation where I have a user model & a department model.
MODEL - User.php
var $hasAndBelongsToMany = array(
'Department' => array('className' => 'Department',
'joinTable' =>
'departments_users',
I did read those, and realize that Effect.Appear only works on a style
declared within the div tag, I have done that. However beyond that I
don't see anything on those pages that relate to this problem. Unless
Effect.Fade doesn't work on styles that are set in that matter.
I figured it was a Java
Hey guys,
I feel I still need to apologise for my utter stupidity on losing my
other Google Mail account.
Not only because I was stupid but, now, my stupidity has harmed the
Portuguese CakePHP community.
In the past hours I was alerted that the cake-php-pt GG was deleted.
I immediately began to
Ok, so here's the scenario ...
A user can have multiple webpages in their account, and when they set
them up, they must choose the type (ex: blog, gallery, etc). So User
HABTM webpage_type ... where users_webpage_types has additional fields
for URL, title, etc.
The thing I'm running into is upon
Apologies in advance. GMAIL auto-sent my last emal before finishing!
hi there
thsi group is great firstly and i have been doing pretty well with cake.
however i was trying something that is either
absurdly simple or not possible. i want to get my model out (via db) but i
want to sort it bas
hi there
thsi group is great firstly and i have been doing pretty well with cake.
however i was trying something that is either
absurdly simple or not possible. i want to get my model out (via db) but i
want to sort it based on the count of a set
of children (has many). The simplist example is
Ar
Well, assuming the Docs are correct (and I understand it properly),
that should only apply to updates ("If true (default value) cake will
first delete existing relationship records in the foreign keys table
before inserting new ones, when updating a record. So existing
associations need to be pass
Hi,
There are two way to handle this.
Add these lines above your other users routing rules. If you put it below your
other rules, then the router will think "login" is a username. This is not an
advisable approach since you can no longer have users with the names "login" or
"logout", and ever
Goes to show I should read more carefully :)
I guess the title of the post made me jump the gun...
You say "an user has 2 of the same webpage_type"
Does it mean that in your join table you have something like: ?
user_id | web_page_type_id
-
7 |
Exact error message? What is not found?
On 3 Okt., 23:05, dtrax84 <[EMAIL PROTECTED]> wrote:
> Hi,
> Tried running cakephp on my server with php-cgi with mod_rewrite
> enabled and got the error 404 message. Any ideas?
--~--~-~--~~~---~--~~
You received this message
Silly question I know, but is there a other way beside "exec()" and
"ob_start()" to call the functionality of a cake shell from inside a
controller?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To
Do you know what 'unique'=>true does?
Btw, there really isn't any need to define default values for your
associations if you follow the conventions.
On Oct 3, 6:10 pm, Brenton B <[EMAIL PROTECTED]> wrote:
> Ok, so here's the scenario ...
>
> A user can have multiple webpages in their account, and
Hi,
Tried running cakephp on my server with php-cgi with mod_rewrite
enabled and got the error 404 message. Any ideas?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send emai
Hi,
I am having problems running cakephp on my server (Server API: CGI)
using mod_rewrite. Does anyone has the same issue?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send
Hi,
I am getting a weird issue when i change the default layout being
displayed.
Normally the following code works as expected ($scrips_for_layout is
populated):
(app/views/layout/default.ctp)
meta('icon');
$html->css('cake.generic', null, array(), false);
echo $scripts_for_layout;
?>
Excep
Great, that helped a lot. A follow up issue I am having is what is
the correct way to handle such things as login / logout functions in
the user controller so that when I go to http://example.com/users/logout,
it doesn't query the database and it performs the logout functions.
Thanks again for y
Great, that helped a lot. A follow up issue I am having is what is
the correct way to handle such things as login / logout functions in
the user controller so that when I go to http://example.com/users/logout,
it doesn't query the database and it performs the logout functions.
Thanks again for y
I don't understand why this issue still lingers on and on in cakePHP.
Why not just have the following syntax:
(If you only have 1 field)
var $displayField = 'last_name';
(If you have multiple fields)
var $displayField = array(
'fields' = array(
'last_name',
'first_name'
If it's a one to many relationship (author has many books, each book
has one author):
In Book Model you stick this:
var $belongsTo = array ('Author');
In Author Model:
var $hasMany = array ('Book');
http://book.cakephp.org/view/78/Associations-Linking-Models-Together
I'd recommend going throug
Note also you have to have your tables defined according to the
CakePHP syntax. Each one should have an "id" key column. Then the Book
table should have an author_id field to link the author.
On Oct 3, 2:54 pm, qwanta <[EMAIL PROTECTED]> wrote:
> If it's a one to many relationship (author has man
thanx for ur time.
- ya u r rite that htmlhelper is easy way to genrate tables cell and
headers..
but i m trying to learn some code myself.. :p
- i m trying to made relationship b/w books and authors tables...i think its
relation is not make properly.
-how to make foreign key?..i think thats the pr
What you probably want to do is take a look at what you have in the
$books array at the end of your controller. A quick and dirty way is
to put a var_dump($books); as last statement in your controller
function. The contents will then show up at the top of your view.
Check if the ['Author']['name']
Did you check this var at the auth component?
/**
* The name of an optional view element to render when an Ajax request
is made
* with an invalid or expired session
*
* @var string
* @access public
*/
var $ajaxLogin = null;
Never tried it, but i guess is something meant to do what
> if(isset($this->data['Product']['user_id'] = $user_id)) {
> if(isset($this->data['Product']['user_id'] = $this->Auth->user('id');) {
if(($this->Auth->user('id') != null) && isset($this->data['Product']
['user_id']))
{
$this->data['Product']['user_id'] = $this->Auth->user('id');
}
--~--~-
Thanks so much for all the hard work guys!
Special thanks to Mark Story, because bugs I reported were fixed the
next day by him. He's so fast! Thanks for all the hard work Mark!
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Googl
if you are using scaffolding, try change column setting to TINYINT(1),
then in scaffolding you will have Yes / No :)
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email
Hi,
> Is there changelog notes for 1.1.20?
> like:https://trac.cakephp.org/wiki/changelog/1.1.x.x
I'm not aware of a changelog for 1.1, but as there were only a handful
of changes the following view might help:
https://trac.cakephp.org/log/branches/1.1.x.x
--
Daniel Hofstetter
http://cakebaker
The association should be picture->gallery->location
when i perform a search
picture->find()
then i need as result to route the image
data[Location]
data[Gallery]
data[Picture]
in sql i would write:
FROM dp_pictures
LEFT JOIN galleries ON gallery_id = galleries.id
LEFT JOIN locations ON
Hi I would prefer to get the value from the session.
When I do
if(isset($this->data['Product']['user_id'] = $user_id)) {
if(isset($this->data['Product']['user_id'] = $this->Auth->user('id');) {
I get this error
Parse error: syntax error, unexpected '=', expecting ',' or ')' in
C:\xampp\htdocs\
When you post a form, the selected value of a select list is in the
data array as any other form field.
> Hello all, how do I get the selected value from a select drop down
> box. Basically I want to redirect based on the returned value however
> I can not figure out how to get the selected va
There were a number of problems with fixture importing in RC2, which
were corrected. Perhaps one of these corrections broke your tests?.
For examples on fixture use check the fixture test. You can also try
specifying which connection you want to use so connection => default
-Mark
On Oct 3, 5:07
>
> ..the comment "PERFORM BUSINESS LOGIC" should immediately
> let you think that something is not 100% MVC ..you are
> performing LOGIC inside a MODEL, and not just model data
> handling.
So, where I have to do the business logic?
For example, I have a Product Object, and the product has some
$count = $this->find('count',array('conditions'=>
$data,'recursive'=>-1));
should be
$count = $this->find('count',array('conditions'=>array('state'=>
$data),'recursive'=>-1));
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google
Assuming you want the currently logged in administrator.
$this->data['Product']['user_id'] = $this->Auth->user('id');
Otherwise, you'll need a belongsTo association in your Product model,
and allow scaffolding to show a user drop down list.
--~--~-~--~~~---~--~~
Maybe this is a little late but perhaps it will save some other soul
some trial and error.
I'm using 1.2 branch so this may not work for 1.1.
To change the default class name for the div that surrounds the input
when using form helper use the options array like so:
echo $form-
>input('tst_input',a
Just assign the values to the data array
$this->data['Product']['user_id'] = $user_id
Or put user_id as a hidden field in the form.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this gr
Hi, I am busy reworking a bakesale script based on cake, my OOP php is
not that good. Maybe someone can point me here in the right direction.
I want to change a script the add a product and in sert in the db the
user_id in the product table - which should come from the User.id
function admin_add(
What errors are you getting? What is the problems that you are seeing?
On Oct 3, 6:30 am, uddi <[EMAIL PROTECTED]> wrote:
> I have read the multilanguage support in cakePHP article (http://
> bakery.cakephp.org/articles/view/p28n-the-top-to-bottom-persistent-
> internationalization-tutorial). But
Hi again,
And what is the problem here, what query is generated?
Regards,
Piotr
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email to cake-php@googlegroups.com
To unsu
I want a random picture for each gallery
Is it possible to realise with a relation like this ?
Class Gallery extends AppModel {
var $hasOne= array( 'RandomImage' =>
array('className' => 'Picture',
Hi I don't know how too but.. you can steal some ideas how to handles
images at http://www.bakesalehq.com/ since it is a ecommerce
site/template that uses images
On Fri, Oct 3, 2008 at 12:43 PM, AceStudio <[EMAIL PROTECTED]> wrote:
>
> I am developing a social community and would like members pro
Fantastic! You guys rule!
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
View:
$options = array(
'/things/view/%id' => 'View this thing',
'/things/index' => 'Go back to the index'
);
echo $form->input('WhatToDo.next', array('options' => $options,
'label' => 'What do you want to do next?'));
Controller:
// ...
if ($this->Thing->save($this->data)) {
$this->Sessi
Yes you can define additional indexes in the indexes key. However,
you will not be able to force innodb foreign key with references, as
this feature is not supported in all databases it was not implemented
in the schema system.
On Oct 2, 8:00 pm, luissquall <[EMAIL PROTECTED]> wrote:
> I cannot
Hi,
> can anyone help me with this problem???
Yes. Two ideas.
1st, worse - use redirections, so in case your url is /searches/index?
search=linkin redirect it to /searches/index/linkin/. Redirections
always give us some overhead, also this way the search results won't
be seo.
2nd, better - you
Hello all, how do I get the selected value from a select drop down
box. Basically I want to redirect based on the returned value however
I can not figure out how to get the selected value?
--~--~-~--~~~---~--~~
You received this message because you are subscribed t
$this->passedArgs['patientId']
or
$this->passedArgs('patientId)
On Oct 2, 11:54 am, "jitka (poLK)" <[EMAIL PROTECTED]> wrote:
> debug($this->passedArgs);
>
> My point is - I do not think it is necessary to use named argument for
> your need.
--~--~-~--~~~---~--~~
when i click on any link and immediately i click on other the cakephp
application redirects the application on login page.
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send
I have read the multilanguage support in cakePHP article (http://
bakery.cakephp.org/articles/view/p28n-the-top-to-bottom-persistent-
internationalization-tutorial). But i am not able to run this example.
Please help if anyone have any other reference Url or guidence
material from where i can ge
I am developing a social community and would like members profile to
show their pictures or avatar. Cake documentation doesn't deal with
this at all. Please i'd appreciate if someone treated this
--~--~-~--~~~---~--~~
You received this message because you are subsc
hi everybody,
I'm not a MVC guru,but in my opinion, the fact
that a view can import something and invoke
actions not performed by a controller, but from
a model, breaks somehow the MVC pattern.
Maybe if you need some action to manipulate data
of a model before display them, you should use
the afte
hi all,
i m very new in cakePHP, pls help me some one about this error, which
is headeach for me.
=> i m getting error of [Undefined index] in abc view file.i m
pasting code here if some 1 got it then pls help me.
thanx
=>this controller file code for index...
function index() {
$this->Book->rec
hi everybody,
I'm not a MVC guru,but in my opinion, the fact
that a view can import something and invoke
actions not performed by a controller, but from
a model, breaks somehow the MVC pattern.
Maybe if you need some action to manipulate data
of a model before display them, you should use
the afte
Or you can specify only the fields you're interested in via 'fields'
array. in Model::find()
On 3 Říj, 00:22, Steveston <[EMAIL PROTECTED]> wrote:
> For example: a typical university project, I have users, user_courses
> (for instructors), user_enrolls (for students), courses, events (each
> cour
hello fiends,
i have a problem using pagination pls help me out.
the link shown on the url is different from that of the links shown on
the page nos.
what i mean to say is the links that i'm gettin whin i point the mouse
on the page is /searches/index/linkin/page:2
but when i search foe an entit
Router::connect('/users/:username',
array('controller'=>'users','action'=>'index'),array('pass'=>array('username')));
This routes /users/bobcostas to the function index( $username ) method
of the controller, with the username passed as a parameter.
Router::connect('/users/:username/:action',
arr
The only complain that I found in the API documentation, is that there
are not clear explanations about the parameters that a method expects
(usually as an array) or class attributes are not explained too.
Altought there is the source code; in many cases the source code
itself is the best document
Congratulation!! Core Team
On Fri, Oct 3, 2008 at 6:15 PM, tracyfloyd <[EMAIL PROTECTED]> wrote:
>
> Fantastic! You guys rule!
> >
>
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this
I am also getting the same problem. I want to paginate the search results
in a fashion that the search url can be bookmarked. but i am not able to do
so. The problem being that when the query is a get string, the submission to
the searches controller looks like
http://x.com/searches/index?q=mystri
Is there changelog notes for 1.1.20?
like: https://trac.cakephp.org/wiki/changelog/1.1.x.x
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email to cake-php@googlegroups.c
You don't need routing (Router) becouse webroot's files like images
are accessed by web server directly, not through cake.
you can create url to images in your views:
For dataset: 1172271600 mylocation mygallery 0001
$img_url = 'event/'.date(Y_m_d).'mylocation_mygallery_0001.jpg';
echo $html->ima
I think the book is on the right way. Think a half year back! Nearly
nothing was documented.
Now, evertime I search a feature I look at the proper sections of the
book.
If you need help about Formhelper, look at the Built-In Helpers
chapter. It is structured very well, and you find many things wi
I am new to this, I just took over this site which was written in
cakephp and I have never seen or used it before.
On Oct 2, 8:54 pm, "3lancer.eu" <[EMAIL PROTECTED]> wrote:
> Hi,
>
> Well, I don't know why do you expect that to work. Please read the
> chapter on routes:http://book.cakephp.org/vi
Hey CakeGroup,
I want to route my Images in a specific schema. Can i use the
Route::connect function for this ?
And where should i put the logic for this? In the Controller, Model
oder View?
The schema:
/img/events/:date(Y_m_d)/:location_:gallery_:number_thumb.jpg
For example the dataset is thi
Thx, for the info.
On Oct 2, 7:30 pm, mark_story <[EMAIL PROTECTED]> wrote:
> I don' think this is going to be changed before 1.2 is released but it
> is pretty easy to do in your models.
>
> http://mark-story.com/Posts/view/auth-and-acl-automatically-updating-...
>
> tutorial for doing it with u
I am having problems with fixtures which use $import = "SomeModel".
I am getting the usual "Database table some_models for model SomeModel
was not found."
Sometimes it helps to change it to $import = array('table' =>
'some_models'); but this doesn't solve it all the time. Especially if
there are
This is rather a Javascript problem, not Cake.
Have a look at
http://github.com/madrobby/scriptaculous/wikis/effect-appear
http://github.com/madrobby/scriptaculous/wikis/effect-fade
which should help you.
--~--~-~--~~~---~--~~
You received this message because y
thank you brendon
On Oct 1, 1:54 am, BrendonKoz <[EMAIL PROTECTED]> wrote:
> http://cakephp.org/jobshttp://withcake.com/
>
> On Sep 28, 4:33 am, evert0n <[EMAIL PROTECTED]> wrote:
>
> > Hi, guys anyone need a hand for cakephp projects?
>
> > I'm avaliable for any opportunities asfreelance.
--~--~
Over-engineer much? ;-)
echo $model['boolField'] ? 'Yes' : 'No';
On 3 Oct 2008, at 17:08, Kanten wrote:
>
> Hi,
>
> I have a MySQL table with lots of boolean fields (BOOL) and when
> viewing these in my view I would like to output "Yes" or "No" instead
> of "1" or "0".
>
> I have experimented a
till now what i've made is a searches controller. this controller is
ment to search either a user or an entity in the database.
the first line of my index action is
function index($searchby = 'entity')
this funct works fine if i have to search for an entity, but when i
search for a user it shows m
Hi,
I have a MySQL table with lots of boolean fields (BOOL) and when
viewing these in my view I would like to output "Yes" or "No" instead
of "1" or "0".
I have experimented a bit with doing stuff like this in my controller:
foreach (array_keys($data['BrugadaProfile']) as $key):
72 matches
Mail list logo
