Re: The first word in $(MAKEFLAGS) is not a group of short options

2025-02-10 Thread Paul Smith
On Mon, 2025-02-10 at 02:01 +0900, Masahiro Yamada wrote: > The first word in $(MAKEFLAGS) is not a group of short options. > >     $(MAKE) MAKEFLAGS=--no-print-directory SUBMAKE=1 If you override the value of MAKEFLAGS as a command-line variable assignment, then the value you spe

Re: The first word in $(MAKEFLAGS) is not a group of short options

2025-02-09 Thread Dmitry Goncharov
On Sun, Feb 9, 2025 at 12:04 PM Masahiro Yamada wrote: ... > This is no longer true when MAKEFLAGS is set > via the command line. A command line definition of MAKEFLAGS is a bad idea. https://savannah.gnu.org/bugs/?62469 regards, Dmitry

The first word in $(MAKEFLAGS) is not a group of short options

2025-02-09 Thread Masahiro Yamada
The first word in $(MAKEFLAGS) is not a group of short options. The manual says as follows: "Recall that MAKEFLAGS will put all single-letter options (such as ‘-t’) into the first word, and that word will be empty if no single-letter options were given. To work with this, it’s helpful to