Gregory Marton <[EMAIL PROTECTED]> writes:
> Hi folks,
>
> I'm trying to write a meaningful comparison operator for
> procedures.
Out of interest, why?
> Clearly this wants more than procedure-source, because
> variables in the source may be bound to different values in the
> procedure-environme
Hi folks,
I'm trying to write a meaningful comparison operator for procedures.
Clearly this wants more than procedure-source, because variables in the
source may be bound to different values in the procedure-environment.
I expected something like this to work:
(define foo 3)
(define bar (lamb
