Am 22.08.2024 um 08:54 schrieb Philip Rowlands:
On Wed, 21 Aug 2024, at 18:29, Nathan Hays via GNU coreutils Bug Reports wrote:
Test:
~~~bash
testvar=''
[ -n $testvar ]
echo -n unquote exit $?
[ -n "$testvar" ]
echo -n quote exit $?
[ -z $testvar ]
echo -z unquote exit $?
[ -z "$testvar" ]
ech
On Wed, 21 Aug 2024, at 18:29, Nathan Hays via GNU coreutils Bug Reports wrote:
> Test:
> ~~~bash
> testvar=''
> [ -n $testvar ]
> echo -n unquote exit $?
> [ -n "$testvar" ]
> echo -n quote exit $?
> [ -z $testvar ]
> echo -z unquote exit $?
> [ -z "$testvar" ]
> echo -z quote exit $?
> ~~~
For t
I don't see a bug there. 'test' is behaving as documented.
Expectation:
`var=''; [ -n $var ]; echo $?` should NOT return `0`
This expectation is incorrect, because that command should exit with
status 0. This is because the command '[ -n $var ]' is equivalent to:
[ -n ]
which is equivale
# ENV #
Ubuntu 22.04 LTS
COREUTILS version 8.32-4.1ubuntu1.2
*Note could be specific to Ubuntu but I believe I confirmed in source*
# Observed Behavior #
Expectation:
`var=''; [ -n $var ]; echo $?` should NOT return `0`
Reality:
`var=''; [ -n $var ]; echo $?` returns `0`
*Note that this behav
