One IFS non-whitespace is stripped at the end of a word during word splitting

Hi, I was trying to understand the part of the documentation on word splitting. I realized that without some experiments: https://gist.github.com/x-yuri/6c6b375e7b0721a323960baaedf2a649 I wasn't sure I understood it correctly. And one of the experiments revealed that: $ bash -c 'IFS=x; a=xa; f(

Re: One IFS non-whitespace is stripped at the end of a word during word splitting

On Sun, Dec 8, 2024, at 3:27 AM, Yuri Kanivetsky wrote: > $ bash -c 'IFS=x; a=ax; f() { for arg; do echo "($arg)"; done; }; f $a' > (a) > > $ bash --version > GNU bash, version 5.2.37(1)-release (x86_64-pc-linux-gnu) > > I.e. IFS non-whitespaces are not stripped at the beginning of a word, > but if

Re: One IFS non-whitespace is stripped at the end of a word during word splitting

On Sun, Dec 08, 2024 at 10:27:33 +0200, Yuri Kanivetsky wrote: > $ bash -c 'IFS=x; a=ax; f() { for arg; do echo "($arg)"; done; }; f $a' > (a) Another responder has already given an explanation, but just for redundancy: The good news is that there's